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leva [86]
4 years ago
12

The median of the set of prime numbers between 8 and 54 is

Mathematics
2 answers:
tino4ka555 [31]4 years ago
8 0

Answer: 30 I believe? :P

Step-by-step explanation: gather all prime numbers between 8 & 54 and find the number in the middle. in this case, there is an even amount of terms, so add the two middle numbers and divide by 2

soldier1979 [14.2K]4 years ago
3 0

Answer:

<em>median = 30</em>

Step-by-step explanation:

Given that the set includes all prime numbers between 8 and 54.

A prime number is only divisible by one and itself, so it only has a factor of 1 and itself. The prime numbers between these two numbers (8 and 54) include: 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, and 53.

Since there is a total of 12 numbers, the median is the number that makes an even amount of numbers on each side, which would make the median between 12 numbers, the middle of the 6th and 7th.

6.5

1 2 3 4 5 6 | 7 8 9 10 11 12

^ ^ ^ ^ ^ ^ ^ ^ ^ ^ ^ ^

1 2 3 4 5 6 1 2 3 4 5 6

11 (1st), 13(2nd), <u>17(3rd)</u>, <u>19(4th)</u>, 23(5th), 29(6th), 31(7th), 37(8th), <u>41(9th)</u>, <u>43(10th)</u>, 47(11th), 53(12th).

This means the median, or the 2nd quartile of the quartiles is (18+42)/2 = 30 or 29+31/2 = 30.

18 30 42

11 13 17 | 19 23 29 | 31 37 41 | 43 47 53

^ ^ ^(Q1)^ ^ ^(Q2)^ ^ ^(Q3)^ ^ ^

1 2 3 4 5 6 1 2 3 4 5 6

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Consider the following operations on the number 8.82 x 10^-2. Without using a calculator, decide which would give a significantl
Ksenya-84 [330]

Correct question is;

Consider the following operations on the number 8.85 x 10^(-2). Without using a calculator, decide which would give a significantly smaller value than 8.85 x 10^(-2), which would give a significantly larger value, or which would give essentially the same value.

A) 8.85 × 10^(-2) + 6.69 × 10^(5)

B) 8.85 x 10^(-2) - 6.69 x 10^(5)

C) 8.85 x 10^(-2) x 6.69 x 10^(5)

D) 8.85 × 10^(-2) ÷ 6.69 × 10^(5)

Answer:

Option A & B yield essentially the same value.

Option C yields a significantly smaller value

Option D yields a significantly larger value

Step-by-step explanation:

Since given value for the operations is in 10^(-2) indices, then let's convert the operations numbers from 10^(5) indices to 10^(-2).

Thus;

6.69 × 10^(5) = (6.69 × 10^(-7)) × 10^(-2)

Thus;

A) 8.85 × 10^(-2) + 6.69 × 10^(5) is now;

8.85 × 10^(-2) + ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 + (6.69 × 10^(-7))] × 10^(-2)

The 10^(-7) indices indicates that the initial value of 8.85 × 10^(-2) would not change much and would essentially be the same

B) 8.85 x 10^(-2) - 6.69 x 10^(5) is now;

8.85 × 10^(-2) - ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 - (6.69 × 10^(-7))] × 10^(-2)

Again the 10^(-7) indices indicates that the initial value of 8.85 × 10^(-2) would not change much and would essentially be the same.

C) 8.85 x 10^(-2) x 6.69 x 10^(5) is now;

(8.85 × 10^(-2)) × ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 × (6.69 × 10^(-7))] × 10^(-2)

When we multiply 8.85 by 6.69 × 10^(-7), the value gotten will be way lower than the initial value of 8.85.

Thus,this operation will give a significantly smaller value.

D) (8.85 × 10-2) ÷ (6.69 × 10^5) is now;

(8.85 × 10^(-2)) ÷ ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 ÷ (6.69 × 10^(-7))] × 10^(-2)

When we carry out the operation:

8.85 ÷ (6.69 × 10^(-7)), it is essentially equal to (8.85 × 10^(7))/6.69.

This means that the new value would be significantly larger than the initial value of 8.85.

Thus,this operation yields a significantly larger value.

4 0
3 years ago
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