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zloy xaker [14]
3 years ago
14

What is the area of a triangle with a base of 7 cm and a hight of 4 cm

Mathematics
1 answer:
Eva8 [605]3 years ago
4 0

Answer:

14 cm²

Step-by-step explanation:

Using the formula given to calculate the area

with b = 7 and h = 4, then

A = \frac{1}{2} × 7 × 4 = 0.5 × 28 = 14 cm²

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When an equation is written in the form Ax + By = C [picture attached] help pls
balu736 [363]

Answer:

B. Standard Form

Step-by-step explanation:

Ax+By=C is in Standard Form of a linear function

8 0
2 years ago
What is the answer to this problem 3z+4=34
finlep [7]
Solve for z

3z+4=34

Subtract 4 from both sides. 

= 3z=30

Divide both sides by 3

z=10


Hope I helped! :D

3 0
3 years ago
Read 2 more answers
The data below represent the weight, in kilograms, of 15 containers shipped from
Nikolay [14]

Answer:

(A) Maximum = 100 kg.

(B) Lower quartile = 55 kg.

(C) Minimum = 45 kg.

(D) Upper quartile = 93 kg.

(E) Median = 81 kg.

Step-by-step explanation:

A box-plot, also known as a box and whisker plot is a method to demonstrate the distribution of a data-set based on the following 5 number summary,

  1. Minimum (shown at the bottom of the chart)
  2. First Quartile (shown by the bottom line of the box)
  3. Median (or the second quartile) (shown as a line in the center of the box)
  4. Third Quartile (shown by the top line of the box)
  5. Maximum (shown at the top of the chart).

The data provided for the weight, in kilograms, of 15 containers shipped from  a factory in one week is as follows:

S = {45, 51, 53, 55, 55, 65, 75, 81, 84, 87, 93, 93, 95, 96, 100}

The data is already arranged in ascending order.

The maximum value is:

Maximum = 100 kg.

The first quartile is the median value of the first half of the data.

The first half of the data is:

S₁ = {45, 51, 53, 55, 55, 65, 75}

The median of this data set is the middle value, i.e. 4th value.

So, the  first quartile is:

Lower quartile = 55 kg.

The minimum value is:

Minimum = 45 kg.

The third quartile is the median value of the second half of the data.

The second half of the data is:

S₂ = {84, 87, 93, 93, 95, 96, 100}

The median of this data set is the middle value, i.e. 4th value.

So, the third quartile is:

Upper quartile = 93 kg.

The The median of the data set is the middle value, i.e. the 8th value.

Median = 81 kg.

6 0
3 years ago
C^2cos^2 B+ b^2cos^2 C + bc cos (B - C) = 1/2(a^2+b^2+ c^2)​
melisa1 [442]

Answer:

n

me vale

Step-by-step explanation:

spanish hgjddjzfurdoydoydotroyd6odo6eoyeoydtodyodo6do55od5od5odo5dtodtofpydypff6

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5 0
2 years ago
Intr o scadere scazatorul este egal cu cel mai mic nr impar de patru cifre iar diferenta este cu 321 mai mica.Care este descazut
Nat2105 [25]
<span>descendentul este 80.25</span>
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