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4 years ago

PLZ help 50 points and brainliest6 + 3(6x - 2) = -12

Mathematics

2 answers:

tatiyna4 years ago

7 0

You need to isolate/get x by itself in the equation

6 + 3(6x - 2) = -12 Distribute/multiply 3 into (6x - 2)

6 + (3)6x - (3)2 = -12

6 + 18x - 6 = -12 Combine like terms (6 and -6)

18x = -12 Divide 18 on both sides to get x by itself

$x = -\frac{12}{18}$ Simplify

$x=-\frac{2}{3}$

PROOF

$6+3(6(-\frac{2}{3} )-2)=-12$ Plug in -2/3 into x, then multiply 6 and -2/3

6 + 3(-4 - 2) = -12 Simplify what's in the parentheses

6 + 3(-6) = -12 Multiply 3 and -6

6 - 18 = -12

-12 = -12

fgiga [73]4 years ago

7 0

6 + 3(6x - 2) = -12
6 + 18x - 6 = -12
18x = -12
6x = -4
3x = -2
X = -2/3

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Sami cuts out a rectangle that has a perimeter of 48 inches and a length of 13 inches.

ddd [48]

Answer:

Width is 11 inches

Step-by-step explanation:

I am not sure what the question is. I think you might be looking for the width length. The perimeter is the distance around a rectangle. If the whole distance around is 48. We have 2 lengths and 2 widths. They tell us that the length is 13. We have two lengths so the lengths add up to 26. We can subtract that from 48 and that leaves us with 22 (48-26) This is the total for the 2 widths. Since the 2 widths are the same length we divide that number by 2 to get 11.

11 + 11+ 13 + 13 = 48

4 0

2 years ago

Farmer Samantha has a cylindrical grain silo with a diameter of 12 feet and a height of 40 feet. The silo is filled with grain t

sammy [17]

Answer:

161,234 pounds of grain will remain in the silo

Step-by-step explanation:

In this question, we are to calculate the amount of grains that will be left in a silo if 20 cows feed on the content for 100 days.

Firstly, we need to calculate the amount of grains present in the silo.

This we can do by first calculating the volume of the silo. Since it is cylindrical in shape, we apply the formula for the volume of a cylinder.

Mathematically, the volume of a cylinder is

V = pi * r^2 * h

Here we have the r = D/2 = 12/2 = 6 feet and h = 40 feet. Plugging this , we have;

V = pi * 6^2 * 40 = 1440pi cubic feet

Now, per cubic feet, we have a weight of 48 pounds. The weight of grains thus present in the silo is thus;

1440pi * 28 = 1440 * pi * 48= 69,120pi pounds of grain

Let’s calculate what the cows would feast on. That would be 20 * 28 * 100 = 56,000 pounds of grains

Now we need to know what will remain. We just need to subtract what is consumed by the cows from we have inside the silo

What is inside the silo would be 69,120 * 22/7 = apprx 217,234 pounds

What will remain is thus 217,234 - 56,000 = 161,234 pounds of grain

3 0

3 years ago

Please help me! graph y=3/4x-1/2

andreev551 [17]

Use the site called Desmos, it's a graphing calculator and should help you in all the ways you need. It isn't complex. Just put that equation in a box and it graphs it for you.

4 0

3 years ago

Read 2 more answers

When QS=6x and CS=5x-8, what is AB?

patriot [66]

Answer:

AB = x+ 8

Step-by-step explanation:

Given : QS=6x and CS=5x-8

From the given figure,

QS = QC + CS

We are given with QS and CS

Replace it the above equation

6x = QC + 5x -8

Solve for QC

Subtract 5x on both sides

x = QC + -8

Add 8 on both sodes

QC= x + 8

QABC is a rectangle

QC = AB

So AB = x+ 8

4 0

4 years ago

Perform the indicated row operations, then write the new matrix.

Studentka2010 [4]

The matrix is not properly formatted.

However, I'm able to rearrange the question as:

$\left[\begin{array}{ccc}1&1&1|-1\\-2&3&5|3\\3&2&4|1\end{array}\right]$

Operations:

$2R_1 + R_2 ->R_2$

$-3R_1 +R_3 ->R_3$

Please note that the above may not reflect the original question. However, you should be able to implement my steps in your question.

Answer:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

Step-by-step explanation:

The first operation:

$2R_1 + R_2 ->R_2$

This means that the new second row (R2) is derived by:

Multiplying the first row (R1) by 2; add this to the second row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by 2

$2 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}2&2&2|-2\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}2&2&2|-2\end{array}\right] + \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}0&5&7|1\end{array}\right]$

The second operation:

$-3R_1 +R_3 ->R_3$

This means that the new third row (R3) is derived by:

Multiplying the first row (R1) by -3; add this to the third row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by -3

$-3 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right] + \left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}0&-1&1|4\end{array}\right]$

Hence, the new matrix is:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

3 0

3 years ago

Read 2 more answers

PLZ help 50 points and brainliest6 + 3(6x - 2) = -12​

PLZ help 50 points and brainliest6 + 3(6x - 2) = -12