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8_murik_8 [283]
3 years ago
12

A football coach walks 24 meters eastward, then 12 meters

Physics
1 answer:
elena-14-01-66 [18.8K]3 years ago
4 0

Answer:

Distance magnitude = 24 meters

The direction of the displacement = Eastward

Explanation:

The distance walked by the football coach eastward = 24 meters

The distance walked by the football coach westward = 12 meters

Then the distance walked by the football coach eastward = 36 meters

Finally, the distance walked by the football coach westward = 22 meters

The total distance walked by the coach eastward  = 24 + 36 = 60 meters

The total distance walked by the coach westward  = 12 + 22 = 34 meters

Taking x-direction as positive, we have;

The magnitude of the distance = 60 - 34 = 24 meters,

The direction of the coach = Eastward.

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a trcuk weighs four times as much as a stationary car. if teh truck coasts into the car at 12 km/s and they stick toegther, what
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  v=9.6 km/s

Explanation:

Given that

The mass of the car =  m

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The final velocity when they stick = v

If there is no any external force on the system  then the total linear momentum of the system will be conserve.

Pi = Pf

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v=\dfrac{48}{5}\ km/s

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a student compared two samples of matter. he recorded the results in the chart. Sample A: Appearance: shiny and yellow. Sample B
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What is the value of relative humidity when the air is saturated?​
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100 percent

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A golfer hits a shot to a green that is elevated 3.20 m above the point where the ball is struck. The ball leaves the club at a
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16.17 m/s

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h = 3.2 m

u = 18.1 m/s

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H=\frac{u^{2}Sin^{2}\theta }{2g}

H=\frac{18.1^{2}\times Sin^{2}49 }{2\times 9.8}=9.52 m

The vertical distance fall down by the ball, h'  H - h = 9.52 - 3.2 = 6.32 m

Let v be the velocity of ball with which it strikes the ground.

Use third equation of motion for vertical direction

v_{y}^{2}=u_{y}^{2}+2gh'

here, uy = 0

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v_{y}^{2}=2\times 9.8 \times 6.32

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The resultant velocity is given by

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