<h2><u>Answer:</u></h2>
Cynophobia
<h3><u>Explanation:</u></h3>
Cynophobia originates from the Greek words that signify "dog" (cyno) and "fear" (phobis). An individual who has cynophobia encounters a dread of mutts that is both unreasonable and tenacious. It's something beyond feeling of scaredness whether a dog is barking or an individual is around dogs.
An individual who has cynophobia encounters a dread of dogs that is both silly and constant. Explicit fears, similar to cynophobia, influence somewhere in the range of 7 to 9 percent of the populace. They're regular enough that they're formally perceived in the Diagnostic and Statistical Manual of Mental Disorders,
Answer:
The answer is 1020 meters.
Explanation:
The values given by the problem are:
1. T= The falling time of the rock [Seconds]
2. H=The sound velocity constant [meter/second]
The Velocity normal formula is
V=H/T
340=H/3
340*3=H
This solution considers the physic of the traveling wave sound but not really the rock falling problem, because the problem ask for the height of the cliff not even more.
c. Ben is correct. According to Newton's 2nd law of motion objects with more mass require more force to accelerate.
Explanation:
We can answer this question by using Newton's second law of motion, which states that the net force applied on an object is equal to the product between the mass of the object and its acceleration. Mathematically:
where
F is the net force
m is the mass of the object
a is its acceleration
From the equation, we notice that:
- The force is directly proportional to the mass of the object --> so if the mass increases, the force needed to accelerate the object will increase too
Therefore, the correct answer is
c. Ben is correct. According to Newton's 2nd law of motion objects with more mass require more force to accelerate.
Learn more about Newton's second law:
brainly.com/question/3820012
#LearnwithBrainly
Answer:
PART A
It is always zero
PART B
Answer is : 0
Explanation:
PART A :It is always zero because according to my research, The net electric field inside a conductor is always zero. If the net electric field were not zero, a current would flow inside the conductor. This would build up charge on the exterior of the conductor. This charge would oppose the field, ultimately (in a few nanoseconds for a metal) canceling the field to zero.
PART B: You already know that there is a zero net electric field inside a conductor; therefore, if you surround any internal point with a Gaussian surface, there will be no flux at any point on this surface, and hence the surface will enclose zero net charge. This surface can be imagined around any point inside the conductor with the same result, so the charge density must be zero everywhere inside the conductor. This argument breaks down at the surface of the conductor, because in that case, part of the Gaussian surface must lie outside the conducting object, where there is an electric field.
