Let's see: frequency of cellular phone waves (GSM phones) is (800-1900 MHz). If we look at the table of the electromagnetic spectrum, we can see that this range is contained within the frequencies of the microwaves, which include waves in the range 300 MHz-300 GHz.
So, summarizing, the correct answer is "microwaves".
Weak winds that blow for short periods of time with a short fetch.
From the equations of linear motion,
v² = u² + 2as where v is the final velocity, u is the initial velocity and a is the gravitational acceleration, and s is the displacement,
Thus, v² = u² -2gs, but v=0
hence, u² = 2gs
= 2×9.81×0.43
= 8.4366
u = √8.4366
=2.905 m/s
Hence the initial velocity is 2.905 m/s
Then using the equation v= u +gt .
Therefore, v = u -gt. (-g because the player is jumping against the gravity)
but, v = 0
Thus, u= gt
Hence, t = u/g
= 2.905/9.81
= 0.296 seconds
Water gets to the leaves in the tops of the tallest trees by something called the cohesion-tension theory. Water has two very unique properties called adhesion and cohesion. Cohesion is the tendency of water molecules to stick together with one another. The water sticks together, leaving no room for air, strengthening the "force" of the water going up the tree. The water also sticks to the sides of the xylem inside the tree. In addition to these properties, there are also the factors of negative and positive water potential. For more information, look up more details of the cohesion-tension theory.
The current is defined as the amount of charge Q that passes through a given point of a wire in a time
![\Delta t](https://tex.z-dn.net/?f=%5CDelta%20t)
:
![I= \frac{Q}{\Delta t}](https://tex.z-dn.net/?f=I%3D%20%5Cfrac%7BQ%7D%7B%5CDelta%20t%7D%20)
Since I=500 A and the time interval is
![\Delta t=4.0 min=240 s](https://tex.z-dn.net/?f=%5CDelta%20t%3D4.0%20min%3D240%20s)
the charge is
![Q=I \Delta t=(500 A)(240 s)=1.2 \cdot 10^5 C](https://tex.z-dn.net/?f=Q%3DI%20%5CDelta%20t%3D%28500%20A%29%28240%20s%29%3D1.2%20%5Ccdot%2010%5E5%20C)
One electron has a charge of
![q=1.6 \cdot 10^{-19}C](https://tex.z-dn.net/?f=q%3D1.6%20%5Ccdot%2010%5E%7B-19%7DC)
, therefore the number of electrons that pass a point in the wire during 4 minutes is
![N= \frac{Q}{q}= \frac{1.2 \cdot 10^5 C}{1.6 \cdot 10^{-19}C}=7.5 \cdot 10^{23}](https://tex.z-dn.net/?f=N%3D%20%5Cfrac%7BQ%7D%7Bq%7D%3D%20%5Cfrac%7B1.2%20%5Ccdot%2010%5E5%20C%7D%7B1.6%20%5Ccdot%2010%5E%7B-19%7DC%7D%3D7.5%20%5Ccdot%2010%5E%7B23%7D%20%20)
electrons