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kupik [55]
3 years ago
7

Carlos is looking at a picture of a convergent boundary on which a volcanic arc and a trench are identified. Which type of conve

rgent boundary is Carlos looking at?
an oceanic-continental convergent boundary
an oceanic-arctic convergent boundary
an continental-continental convergent boundary
an oceanic-oceanic convergent boundary
Chemistry
2 answers:
FinnZ [79.3K]3 years ago
8 0
Its a. <span>an oceanic-continental convergent boundary</span>
Andrei [34K]3 years ago
6 0

the answer is a .....

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Fill in the coefficients that will balance the following reaction:
dalvyx [7]

Answer:

C₃H₈₍g₎ + 5O₂₍g₎→  3CO₂₍g₎ + 4H₂O₍l₎

Explanation:

Propane is an alkane that burns in enough oxygen to produce carbon (iv) Oxide and heat as the only by products. Balancing the equation: The number of atoms of each kind on either side should be equal. Hydrogen on the left has eight atoms same as the right side after balancing, oxygen has 10 while carbon has 3 on each side.

6 0
3 years ago
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When 1.2383 g of an organic iron compound containing Fe, C, H, and O was burned in O2, 2.3162 g of CO2 and 0.66285 g of H2O were
uysha [10]

Answer:

\boxed{\text{C$_{15}$H$_{21}$FeO$_{6}$}}

Explanation:

Let's call the unknown compound X.

1. Calculate the mass of each element in 1.23383 g of X.

(a) Mass of C

\text{Mass of C} = \text{2.3162 g } \text{CO}_{2}\times \dfrac{\text{12.01 g C}}{\text{44.01 g }\text{CO}_{2}}= \text{0.632 07 g C}

(b) Mass of H

\text{Mass of H} = \text{0.66285 g }\text{H$_{2}$O}\times \dfrac{\text{2.016 g H}}{\text{18.02 g } \text{{H$_{2}$O}}} = \text{0.074 157 g H}

(c)Mass of Fe

(i)In 0.4131g of X

\text{Mass of Fe} = \text{0.093 33 g Fe$_{2}$O$_{3}$}\times \dfrac{\text{111.69 g Fe}}{\text{159.69 g g Fe$_{2}$O$_{3}$}} = \text{0.065 277 g Fe}

(ii) In 1.2383 g of X

\text{Mass of Fe} = \text{0.065277 g Fe}\times \dfrac{1.2383}{0.4131} = \text{0.195 67 g Fe}

(d)Mass of O

Mass of O = 1.2383 - 0.632 07 - 0.074 157 - 0.195 67 = 0.336 40 g

2. Calculate the moles of each element

\text{Moles of C = 0.63207 g C}\times\dfrac{\text{1 mol C}}{\text{12.01 g C }} = \text{0.052 629 mol C}\\\\\text{Moles of H = 0.074157 g H} \times \dfrac{\text{1 mol H}}{\text{1.008 g H}} = \text{0.073 568 mol H}\\\\\text{Moles of Fe = 0.195 67 g Fe} \times \dfrac{\text{1 mol Fe}}{\text{55.845 g Fe}} = \text{0.003 5038 mol Fe}\\\\\text{Moles of O = 0.336 40} \times \dfrac{\text{1 mol O}}{\text{16.00 g O}} = \text{0.021 025 mol O}

3. Calculate the molar ratios

Divide all moles by the smallest number of moles.

\text{C: } \dfrac{0.052629}{0.003 5038}= 15.021\\\\\text{H: } \dfrac{0.073568}{0.003 5038} = 20.997\\\\\text{Fe: } \dfrac{0.003 5038}{0.003 5038} = 1\\\\\text{O: } \dfrac{0.021025}{0.003 5038} = 6.0006

4. Round the ratios to the nearest integer

C:H:O:Fe = 15:21:1:6

5. Write the empirical formula

\text{The empirical formula is } \boxed{\textbf{C$_{15}$H$_{21}$FeO$_{6}$}}

5 0
3 years ago
Which element mo se na or br contains the most moles of atoms in a 1.0 gram sample?
Fittoniya [83]
To determine this, lets use the atomic mass for each element to determine the corresponding number of moles for a given mass of 1 g.

Mo: 95.94 g/mol
1 g/95.94 g/mol = 0.01042 moles Mo

Se: 78.96 g/mol
1 g/78.96 g/mol = 0.01266 moles Se

Na: 22.99 g/mol
1 g/22.99 g/mol = 0.0435 moles Na

Br: 79.9 g/mol
1 g/79.9 g/mol = 0.0125 moles Br

<em>Thus, the answer is Na.</em>
3 0
4 years ago
Microwave warming Popcorn is a  example of
Viefleur [7K]

Answer:

A

Explanation:

Ttu67j5ri76tio5777t65y75ircyjutfjgtfv

4 0
3 years ago
1 mole = _____________________ _________________ particles
Artist 52 [7]

1 mole = 6.02 * 10^23 atoms

This is known as Avogadro's Number. This value is approximate.

5 0
3 years ago
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