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3 years ago

What is the formula of nitrous acid?

Chemistry

2 answers:

Dahasolnce [82]3 years ago

8 0

HNO2
H = Hydrogen
N = Nitrogen
O = Oxygen
There are 2 oxygen atoms and 1 for the other elements.

podryga [215]3 years ago

3 0

The answer is HNO2. :))

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¿Cuál de las siguientes NO es una característica de los ácidos?

Serga [27]

Answer: B

Explanation: La respuesta es b porque su electricidad y no es un ácido.

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3 years ago

Some common substances and their chemical formulas are listed in the chart.

vesna_86 [32]

Answer:

We heart you don't have all the information you just got some common substances and their chemical formulas are listed in the chart? That we don't have the chart to see which of the substances are elements

Explanation:

sorry about that if you can take a picture of it and repost it I am sure I could answer it for you

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3 years ago

Need help Read each statement. Then, list each predator and each prey.

yanalaym [24]

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3 years ago

The question is in the picture below.

pantera1 [17]

The correct option is A.
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4 years ago

Determine the moles of H+ reacting with the metal based on the following experimental data. 10.00 mL of 1.00 M HCl solution is a

musickatia [10]

Answer:

Approximately $1.876 \times 10^{-3}\; \rm mol$ .

Explanation:

Convert both volumes to standard units (that is: liters.)

$10.00 \; \rm mL = 10.00 \times 10^{-3}\; \rm L = 1.000 \times 10^{-2}\; \rm L$ .
$27.08 \; \rm mL = 27.08 \times 10^{-3}\; \rm L = 2.708 \times 10^{-2}\; \rm L$ .

Number of moles of $\rm HCl$ initially present (in the $10.00\; \rm mL$ solution at $1.00\; \rm M$ .)

$n(\mathrm{HCl}, \, \text{initial}) = \displaystyle c \cdot V = 1.00\times 1.000 \times 10^{-2}= 1.000\times 10^{-2}\; \rm mol$ .

Number of moles of $\rm NaOH$ from the titration:

$n(\mathrm{NaOH}) = c \cdot V = 0.30 \times 2.708 \times 10^{-2} = 8.124 \times 10^{-3}\; \rm mol$ .

$\rm NaOH$ neutralizes $\rm HCl$ at a $1:1$ ratio:

$\rm HCl + NaOH \to NaCl + H_2O$ .

Hence, $n(\mathrm{HCl},\, \text{leftover}) = n(\mathrm{NaOH}) = 8.124 \times 10^{-3}\; \rm mol$ .

$\begin{aligned}&n(\mathrm{HCl},\, \text{consumed}) \\ =& n(\mathrm{HCl},\, \text{initial}) - n(\mathrm{HCl},\, \text{leftover}) \\ =& 1.000\times 10^{-2} - 8.124\times 10^{-3} \\ =& 1.876 \times 10^{-3}\; \rm mol\end{aligned}$ .

3 0

3 years ago