Answer:
I believe that it is the 2nd option.
Explanation:
My reasonings are because C4H10O has 7 isomers. In which 4 are alcohol and the other 3 are ether.
The first option is ethers, specifically ethoxyethane.
The third option is ethers, specifically 1-methoxypropane.
The fourth option is an alcohol, specifically 1- butanol.
Therefore, leads us to the 2nd option that it is NOT an isomer of C4H10O
The most obvious answer for this would be a product i think.
Answer:
E) molality
Explanation:
Molality -
Molarity of a substance , is the number of moles present in a Kg of solvent .
Hence , the formula for molality is given as follow -
m = n / s
m = molality
s = mass of solvent in Kg ,
n = moles of solute ,
Hence , from the given information of the question,
The concentration unit which have Kg of solvent , is molality.
