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dezoksy [38]
3 years ago
6

Identify each of the following mixtures as either homogeneous or heterogeneous and as a solution, a

Chemistry
2 answers:
IceJOKER [234]3 years ago
8 0

Answer:

Cranberry Juice is a Homogeneous Solution.

Explanation:

A Homogeneous solution is identifiable as a solution that looks like it is one single fluid.

A heterogeneous solution would be categorized as a solution that is obviously two different compounds, like oil and water.

A colloid is similar to the way a homogeneous solution is identified, however, colloids have particles suspended in them that are 1 nanometer to 1 micrometer in length (If particles are smaller than 1 nanometer it is considered a homogeneous solution). Colloids can be identified by shining a flashlight into them. If the beam disperses, it's a colloid. If it goes straight through without dispersing, it's a homogeneous solution. A colloid example is Milk.

A Suspension is similar to a colloid, however, the particles in a suspension are larger than 1 micrometer. Particles in a suspension can often be seen with the naked eye, whereas Colloid particles cannot. A suspension's particles will often separate from the base solution in time. A suspension example would be shaking glitter up in a bottle of water.

Lady bird [3.3K]3 years ago
4 0
Cranberry juice at the store
(It’s a Homogeneous Solution)
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How is Carbon obtained and how is it separated from other substances nearby?
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3 years ago
A water sample contains 50Mg of ferric sulfate. determine the normality of the solution
Lesechka [4]

Answer:

Assuming Volume of dolution = 1 liter . The Normality is:

N=3.75\times 10^{-4}N

Explanation:

<u>Normality : </u>It is the gram equivalent of solute per liter of solution. It is represented by N.

Normality=\frac{Number\ of\ equivalent\ weight}{Volume(L)}

Number of  equivalents weight =

\frac{Molar\ mass}{n}

n= acidity of base or basicity of acid

for salts , n = charge present on cation

The relation between Normality and Molarity is :

Normality =Molarity\times n

n = charge present on cation (<u>not moles)</u>

Fe_{2}(SO_{4})_{3} = ferric sulphate

Here <u><em>Fe is cation and its oxidation state is = + 3 so n= 3</em></u>

1. First , calculate the molarity(M)

Molar Mass of  ferric sulfate = Fe2(SO4)3

2(mass of Fe)+3 (mass of S) + 12(mass of O)

= 2(56)+3(32)+12(16)

= 400 grams

Molarity =\frac{Moles}{Volume}

Moles=\frac{mass}{Molar\ mass}

Molar mass = 400 gram

mass = 50 mg = 0.05 grams

moles=\frac{0.05}{400}

moles=1.25\times 10^{-4}

Molarity =\frac{1.25\times 10^{-4}}{Volume}

let volume = 1 liter

Molarity =\frac{1.25\times 10^{-4}}{1}

molarity=1.25\times 10^{-4}M

<u><em>2. Multiply the molarity with n </em></u>

Normality =Molarity\times n

Normality =1.25\times 10^{-4}M\times n

n = 3

Normality =1.25\times 10^{-4}M\times 3

Normality =3.75\times 10^{-4}N

7 0
4 years ago
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