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mote1985 [20]
2 years ago
15

Which statement accurately describes the bond that forms between carbon and oxygen to create carbon dioxide

Chemistry
1 answer:
Allisa [31]2 years ago
8 0

Answer:

the bond that forms between carbon and oxygen to create carbon dioxide

A polar covalent bond

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What is the oxidation number of phosphorus (P) in phosphoric acid (H3PO4)?
Sedaia [141]

Hey there!:

H is always +1 so the H's have a +3 charge.

O is always -2 so the O's have a -8 charge .

Now, suppose oxidation state for P = X , then :

+3  + X + (-8) = 0      (because of neutral molecule)

x = 8 - 3

x = + 5

So, X = +5 oxidation state.

Answer  C


Hope that helps!

4 0
3 years ago
Please do these questions, will give brainliest
Nata [24]

Answer:

1.c 2.a.3.d 4.a

Explanation:

that is tge answer

3 0
3 years ago
Electrons can jump between energy levels but can never be found in what energy level
yawa3891 [41]

Answer:

Electrons can jump from energy level to energy level (for example energy level 1 to 2) but they can NEVER be found in between energy levels.

6 0
3 years ago
If you dilute 250 mL of 6.4 M lithium acetate solution to a volume of 750 mL, what will the concentration of this solution be?
Tresset [83]
The answer would be 1006.4
3 0
3 years ago
The force of attraction between a divalent cation and a divalent anion is 1.64 x 10-8 N. If the ionic radius of the cation is 0.
Elden [556K]

The radius of the anion is 7.413 nm

<h3>How to calculate the force of attraction between charges</h3>

The force of attraction (F) is given by the formula:

  • F = (1/4π∈r²)(Zc*e)(Za*e)

where:

∈ = permittivity of free space = 8.85*10⁻¹⁵ F/m

Zc = charge on the cation = +2

Zc = charge on the anion = -2

e = charge on an electron = 1.602 * 10⁻¹⁹ C

r = interionic distance

r = rc + ra

where rc and ra are the radius of the cation and anion respectively

F = 1.64 * 10⁻⁸ N

Therefore based on the equation of force of attraction:

1.64 *10⁻⁸ = [1/4π(8.85*10⁻¹⁵)r²](2 * 1.602*10⁻¹⁹)²

r² = 5.63 * 10⁻¹⁷

r = 7.50 nm

Since r = rc + ra

where rc = 0.087 nm

thus, ra = r - rc = 7.50 - 0.087

ra = 7.413 nm

Therefore, the radius of the anion is 7.413 nm

Learn more about ionic radius at: brainly.com/question/2279609

6 0
2 years ago
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