5.20 mol C6H12* (84.2 g/mol C6H12)= 4.38*10^(2) g C6H12.
The answer should only have three significant figures, according to the numbers in the problem.
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Answer:
Which is higher? - 1979571
Explanation:
Answer:
[NaCl] = 1.72 M
Explanation:
First of all, we balance the equation:
BaCl₂ + Na₂SO₄ → 2NaCl + BaSO₄
We convert mass of barium chloride to moles
45 g . 1mol / 208.23g = 0.216 moles
Ratio is 1:2. This means, that our moles of reactant may produce the double of moles, of product.
0.216 . 2 = 0.432 moles of NaCl are been produced.
Molarity is mol/L. We convert volume of water from mL to L
250 mL . 1L /1000 mL = 0.250 L
[NaCl] = 0.432 mol/0.250L = 1.72 M
Cofactors:
A. Coenzyme A (CoA-SH)
B. NAD+
C. Thiamine pyrophosphate (TPP)
D. FAD
E. Lipoic acid in oxidized form
Roles:
E... Attacks and attaches to the central carbon in pyruvate.
A...Oxidizes FADH2.
C...Accepts the acetyl group from reduced lipoic acid.
D... Oxidizes the reduced form of lipoic acid.
B... Initial electron acceptor in oxidation of pyruvate.