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eduard
3 years ago
7

You have 723 ml of 3.99 M HCl. Using a volumetric pipet, you take 326 ml of that solution and dilute it to 976 ml in a volumetri

c flask. Now you take 100.00 ml of that solution and dilute it to 119 ml in a volumetric flask. What is the concentration of hydrochloric acid in the final solution
Chemistry
1 answer:
MakcuM [25]3 years ago
6 0

Answer:

1.12M

Explanation:

The initial concentration of the HCl solution is 3.99M. You are doing 2 dilutions:

In the first you take 326mL and dilute the solution to 976mL; that means you are diluting the solution:

976mL / 326mL = 2.99 times.

The concentration of this solution is:

3.99M / 2.99 = 1.33M

Now, in the second dilution, you take 100mL of the diluted solution and dilute it to 119mL. The concentration of this final solution is:

119mL / 100mL = 1.19 times.

1.33M / 1.19 =

<h3>1.12M</h3>
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