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katen-ka-za [31]
3 years ago
13

You are unsure of the volume of a substance, but you know that it has a density of 4 g/ml and a mass of 16 grams. What is its vo

lume?
Chemistry
1 answer:
avanturin [10]3 years ago
3 0

Answer:

4 mL

Explanation:

Use the density formula, d = m/v

Plug in the density and mass to solve for v:

4 = 16/v

4v = 16

v = 4

So, the volume is 4 mL

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Cylinder with a mass of 12g has a radius measuring 2cm and height of 6cm what is its density
lakkis [162]

Answer:

Given:

m = 12 g, the mass of the cylinder

r = 2 cm, the radius of the cylinder

h = 6 cm, the height of the cylinder.

Calculate the volume, V, of the cylinder.

V = πr²h

  =  π*(2 cm)²*(6 cm)

  = 75.398 cm³

By definition,

density = mass/volume.

Therefore,

density = m/V

            = (12 g)/(75.398 cm³)

            = 0.159 g/cm³

            = 0.16 g/cm³ (nearest hundredth)

Answer: 0.16 g/cm³

8 0
3 years ago
Which of the following will result in a chemical change?
Alinara [238K]
C burning coal in a furnace 
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3 years ago
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If Shauna takes her new kitten to the veterinarian for a check-up and the kitten's weight is recorded as 425 grams , how many po
trapecia [35]

answer: 0.936965

hope this helps

3 0
3 years ago
gaseous methane undergoes complete combustion by reacting with oxygen to form carbon dioxide and water vapor . what is the balan
babunello [35]
CH4(g) + 2 O2(g)  ---->  CO2(g) + 2 H2O(g)
8 0
3 years ago
How many H atoms are in 6.43g x 10^24 molecules of water
kow [346]

Answer:

12.86\times 10^{24} atoms of hydrogen

Explanation:

The molecular formula for a water molecule is H_2O.

From the above formula, we can conclude that 1 molecule of water contains 2 atoms of hydrogen and 1 atom of oxygen.

There are 6.43\times 10^{24} molecules of water.

1 molecule of water = 2 atoms of hydrogen.

∴ 6.43\times 10^{24} molecules of water = 2\times 6.43\times 10^{24}=12.86\times 10^{24} atoms of hydrogen.

Therefore, there are 12.86\times 10^{24} atoms of hydrogen in 6.43\times 10^{24} molecules of water.

5 0
3 years ago
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