Answer:
NaCl+H20
Explanation:
It is a neutralisation reaction in which NaOH is a base and HCl is an acid. On reaction it forms salt and water.
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Answer:
124 g (3 sig figs)
or
124.011 g (6 sig figs
Explanation:
Step 1: Calculate g/mol for AgNO₃
Ag - 107.868 g/mol
N - 14.01 g/mol
O - 16.00 g/mol
107.868 + 14.01 + 16.00(3) = 169.878 g/mol
Step 2: Multiply 0.73 moles by molar mass
0.73 mol (169.979 g/mol)
124 grams of AgNO₃
Answer:
0.2788 M
1.674 %(m/V)
Explanation:
Step 1: Write the balanced equation
NaOH + CH₃COOH → CH₃COONa + H₂O
Step 2: Calculate the reacting moles of NaOH

Step 3: Calculate the reacting moles of CH₃COOH
The molar ratio of NaOH to CH₃COOH is 1:1.

Step 4: Calculate the molarity of the acetic acid solution

Step 5: Calculate the mass of acetic acid
The molar mass of acetic acid is 60.05 g/mol.

Step 6: Calculate the percentage of acetic acid in the solution
