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kipiarov [429]
3 years ago
10

At the surface of Jupiter's moon Io, the acceleration due to gravity is 1.81 m/s2 . A watermelon has a weight of 40.0 N at the s

urface of the earth. In this problem, use 9.80 m/s2 for the acceleration due to gravity on earth.Part A
What is its mass on the earth's surface?

Part B

What is its mass on the surface of Io?

Part C

What is its weight on the surface of Io?
Physics
1 answer:
Mumz [18]3 years ago
8 0

Answer

acceleration due to gravity on Jupiter's moon,g' = 1.81 m/s²

weight of water melon on earth, W = 40 N

acceleration due to gravity on earth, g = 9.8 m/s²

a) Mass on the earth surface

    M = \dfrac{W}{g}

    M = \dfrac{40}{9.8}

           M = 4.08 Kg

b) Mass on the surface of Lo

 Mass of an object remain same.

  Hence, mass of object at the surface of Lo = 4.08 Kg.

c) Weight at the surface of Lo

   W' = m g'

   W' =4.08 x 1.81

   W' = 7.38 N

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An eagle is flying horizontally at a speed of 3.10 m/s when the fish in her talons wiggles loose and falls into the lake 6.10 m
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10.93m/s with the assumption that the water in the lake is still (the water has a speed of zero)

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We use the first equation of motion for a free-falling body to obtain v as follows;

v = u + gt....................(1)

where g is acceleration due to gravity taken as 9.8m/s/s

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h=ut+gt^2/2.................(2)

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since u = 0 for the vertical motion;  equation (2) can be written as follows;

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substituting;

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Putting this value of t in equation (1) we obtain the following;

v = 0 + 9.8*1.12

v = 10.93m/s

5 0
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