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kipiarov [429]
3 years ago
10

At the surface of Jupiter's moon Io, the acceleration due to gravity is 1.81 m/s2 . A watermelon has a weight of 40.0 N at the s

urface of the earth. In this problem, use 9.80 m/s2 for the acceleration due to gravity on earth.Part A
What is its mass on the earth's surface?

Part B

What is its mass on the surface of Io?

Part C

What is its weight on the surface of Io?
Physics
1 answer:
Mumz [18]3 years ago
8 0

Answer

acceleration due to gravity on Jupiter's moon,g' = 1.81 m/s²

weight of water melon on earth, W = 40 N

acceleration due to gravity on earth, g = 9.8 m/s²

a) Mass on the earth surface

    M = \dfrac{W}{g}

    M = \dfrac{40}{9.8}

           M = 4.08 Kg

b) Mass on the surface of Lo

 Mass of an object remain same.

  Hence, mass of object at the surface of Lo = 4.08 Kg.

c) Weight at the surface of Lo

   W' = m g'

   W' =4.08 x 1.81

   W' = 7.38 N

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1. B

2. D

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A 0.600 kg block is attached to a spring with spring constant 15 N/m. While the block is sitting at rest, a student hits it with
gulaghasi [49]

Answer:

8.8 cm

31.422 cm/s

Explanation:

m = Mass of block = 0.6 kg

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x = Compression of spring

v = Velocity of block

A = Amplitude

As the energy of the system is conserved we have

\dfrac{1}{2}mv^2=\dfrac{1}{2}kA^2\\\Rightarrow A=\sqrt{\dfrac{mv^2}{k}}\\\Rightarrow A=\sqrt{\dfrac{0.6\times 0.44^2}{15}}\\\Rightarrow A=0.088\ m\\\Rightarrow A=8.8\ cm

Amplitude of the oscillations is 8.8 cm

At x = 0.7 A

Again, as the energy of the system is conserved we have

\dfrac{1}{2}kA^2=\dfrac{1}{2}mv^2+\dfrac{1}{2}kx^2\\\Rightarrow v=\sqrt{\dfrac{k(A^2-x^2)}{m}}\\\Rightarrow v=\sqrt{\dfrac{15(0.088^2-(0.7\times 0.088)^2)}{0.6}}\\\Rightarrow v=0.31422\ m/s

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4 0
3 years ago
Can someone please help me. idk what to do​
Alex_Xolod [135]

Answer:

-4.5 m/s

Explanation:

Even without doing calculations, we know that a projectile has the same speed coming down as it did going up at the same height.  Since it went up at 4.5 m/s, it returns down at -4.5 m/s.

To prove it with math, use the given information:

v₀ = 4.5 m/s

a = -9.8 m/s²

Δy = 0 m

Find: v

v² = v₀² + 2aΔy

v² = (4.5 m/s)² + 2 (-9.8 m/s²) (0 m)

v = -4.5 m/s

3 0
4 years ago
Please help me!!!
dezoksy [38]
<h2><em>The Answer to Youre Question:</em></h2>

<em>I think it is B.</em>

<em>I hope this helps.</em>

7 0
3 years ago
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