What force acts between earth and the moon
1 answer:
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Answer:
a
b
c
Explanation:
From the question we are told that
The frequency is
The length of the vibrating string is
The mass is
Generally the wavelength is mathematically represented as
=>
=>
Generally the wave speed is
=>
=>
Generally the tension on the wire is mathematically represented as
=>
=>
Explanation:
Given data:
d = 30 mm = 0.03 m
L = 1m
S = 70 Mpa
Δd = -0.0001d
Axial force = ?
validity of elastic deformation assumption.
Solution:
O'₂ = Δd/d = (-0.0001d)/d = -0.0001
For copper,
v = 0.326 E = 119×10³ Mpa
O'₁ = O'₂/v = (-0.0001)/0.326 = 306×10⁶
∵δ = F.L/E.A and σ = F/A so,
σ = δ.E/L = O'₁ .E = (306×10⁻⁶).(119×10³) = 36.5 MPa
F = σ . A = (36.5 × 10⁻⁶) . (π/4 × (0.03)²) = 25800 KN
S = 70 MPa > σ = 36.5 MPa
∵ elastic deformation assumption is valid.
so the answer is
F = 25800 K N and S > σ
Answer:
The only parameter that changes is mass m
It is only necessary to calculate the ratio Eh/Ee
The kinetic energy of the heavy paricle is three times the kinetic energy of an electron