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3 years ago

Which does a reference point provide

1 answer:

5 0

Point of reference - an indicator that orients you generally; "it is used as a reference for comparing the heating and the electrical energy involved"

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Brainliest for correct answer :)

AnnyKZ [126]

All 3 objects have the same mass

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3 years ago

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The ground heats the air through what

Tema [17]

Explanation:

The atmosphere is heated in several ways - heat from the core of the Earth, by radiation from the Sun, conduction from contact with warm land and water, convection to even out the temperature and by absorption of infrared radiation from the warm land and water. The core of the Earth is very hot.

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3 years ago

What can you conclude about the velocity of the object on the graph below

Mars2501 [29]

Answer:

The more time goes on the higher in meters. So most likely more time = closer to terminal velocity. -hope this helps.

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3 years ago

Ayden and Steven are playing catch with a football. Ayden throws the football at a velocity of 15 m/s with an angle of 60° above

Pachacha [2.7K]

1) 1.33 s

2) 8.6 m

3) 19.9 m

Explanation:

The motion of the football is a projectile motion, which consists of two independent motions:

- A uniform motion (=constant velocity) along the horizontal direction

- A uniformly accelerated motion (=constant acceleration) along the vertical direction

The hang time of the football is the time it takes for the football to reach its maximum height. It is given by:

$t=\frac{u_y}{g}$

where

$u_y = u sin \theta$ is the initial vertical velocity of the ball, where

u = 15 m/s is the initial velocity

$\theta=60^{\circ}$ is the angle of projection of the ball

$g=9.8 m/s^2$ is the acceleration due to gravity

Substituting, we find the hang time:

$t=\frac{u sin \theta}{g}=\frac{(15)(sin 60^{\circ})}{9.8}=1.33 s$

The motion of the ball along the vertical direction is a uniformly accelerated motion, so we can use the suvat equation:

$s=u_y t - \frac{1}{2}gt^2$

where:

s is the vertical displacement

$u_y = u sin \theta$ is the initial vertical velocity

t is the time

$g=9.8 m/s^2$ is the acceleration due to gravity

In this part, we want to find the maximum height, so the height reached by the ball when the time is

t = 1.33 s

Therefore, by substituting the values in the equation, we can find the maximum height:

$s=usin \theta t-\frac{1}{2}gt^2=(15)(sin 60^{\circ})(1.33)-\frac{1}{2}(9.8)(1.33)^2=8.6 m$

Here we want to find the horizontal range covered by the ball during its flight.

The horizontal range for a projectile is given by the equation

$d=\frac{u^2 sin(2\theta)}{g}$

where

u is the initial velocity

$\theta$ is the angle of projection

g is the acceleration due to gravity

For the ball in this problem we have:

u = 15 m/s

$\theta=60^{\circ}$

$g=9.8 m/s^2$

Substituting into the equation, we find the horizontal distance covered by the ball:

$d=\frac{(15)^2sin(2\cdot 60^{\circ})}{9.8}=19.9 m$

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4 years ago

During the formation of the aurora borealis, the electrons in an atom experience a change in energy levels. Which statement abou

Elena L [17]

Answer:

They are deflected as Earth’s magnetic field exerts force on them.

Explanation:

(Not for cheating, Just to help)

As solar wind approaches Earth, what happens to the charged electrons?

They are absorbed as Earth’s magnetic field exerts force on them.

They grow stronger as Earth’s magnetic field exerts force on them.

They grow weaker as Earth’s magnetic field exerts force on them.

They are deflected as Earth’s magnetic field exerts force on them.

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3 years ago

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