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3 years ago

Can someone help me please

Physics

1 answer:

Semenov [28]3 years ago

6 0

Answer:

distance and time

Explanation:

like miles per hour, its the measure of how far something went durind a span of time, hours.

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In transverse waves, the medium moves perpendicular to the direction of energy transport? True or false?

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Answer:

This statement is true

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3 years ago

A mosquito flies toward you with a velocity of 2.4 km/h [E]. If a distance of 35.0 m separates you and the mosquito initially, a

tangare [24]

First convert the speed of mosquito to m/s:

So the mosquito is flying at (2,400/3,600) m/s, or ⅔ m/s.

Since you are moving at 2m/s, so this makes the closing velocity between you and the mosquito to be 2⅔ m/s.

Therefore the mosquito will hit your sunglasses at:

35 m / (2⅔ m/s) = 13⅛ seconds.

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⅔ m/s * 13⅛ s = 8¾ m from the mosquito's initial position.

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3 years ago

A 40-cm-long tube has a 40-cm-long insert that can be pulled in and out. A vibrating tuning fork is held next to the tube. As th

Umnica [9.8K]

Answer:

The frequency of the tuning is 1.065 kHz

Explanation:

Given that,

Length of tube = 40 cm

We need to calculate the difference between each of the lengths

Using formula for length

$\Delta L=L_{2}-L_{1}$

$\Delta L=74.7-58.6$

$\Delta L=16.1\ m$

For an open-open tube,

We need to calculate the fundamental wavelength

Using formula of wavelength

$\lambda=2\Delta L$

Put the value into the formula

$\lambda=2\times16.1$

$\lambda=32.2\ cm$

We need to calculate the frequency of the tuning

Using formula of frequency

$f=\dfrac{v}{\lambda}$

Put the value into the formula

$f=\dfrac{343}{32.2\times10^{-2}}$

$f=1065.2\ Hz$

$f=1.065\ kHz$

Hence, The frequency of the tuning is 1.065 kHz

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2 years ago

What is a descriptions of an animal cell's nucleus?

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3 years ago

You are viewing a read out of an oscilloscope that shows you when different voltages in a circuit maximize. If the period of the

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Answer:

The time is $t = 0.02 \ s$