Given :
Initial velocity, u = -15 m/s.
Acceleration , a = 2 m/s².
Time taken to applied brake, t = 2.5 s.
To Find :
The velocity of the car at the end of the braking period.
How far has the car moved during the braking period.
Solution :
By equation :
Now, distance covered by car is :
Hence, this is the required solution.
Answer:
123.2 m/s after 28s
Explanation:
Vi= 0 m/s
a= 4.4 m/s^2
t=28s
Vf after 28s
To find Vf use your kinematics formula Vf=Vi+at
Vi is Zero so it gets removed and the equation becomes
Vf=at
Simply Plug and Solve
Vf= 4.4(28)
Vf=123.2 m/s after 28s
Answer:
Right to left
Explanation:
From right hand thumb rule, the magnetic field at the centre of loop points out of the plane of paper. Thus the straight wire current should create magnetic field into the plane of paper at the centre. Hence the direction of current in long wire should be from right to left
It helps us learn more about the world around us
The banking angle of the curved part of the speedway is determined as 32⁰.
<h3>
Banking angle of the curved road</h3>
The banking angle of the curved part of the speedway is calculated as follows;
V(max) = √(rg tanθ)
where;
- r is radius of the path
- g is acceleration due to gravity
V² = rg tanθ
tanθ = V²/rg
tanθ = (34²)/(190 x 9.8)
tanθ = 0.62
θ = arc tan(0.62)
θ = 31.8
θ ≈ 32⁰
Learn more about banking angle here: brainly.com/question/8169892
#SPJ1