Resistance= Potential Difference/Current
10 Ohm= PD/ 5A
PD= 10 Ohm × 5A
PD=50
Therefore, Potential Difference is B. 50 V
The spring's work output while it is not extended is 5 J.
<h3>What is The Hooke's law ?</h3>
According to Hooke's law, as long as the elastic limit is not exceeded, the extension of a particular material is directly proportional to the force applied. Hence, we must be aware of that F = Ke
F = Applied force
Force constant is K.
Extension = e
F = applied force
Force constant is K.
Extension = e
Using the graph
K = F/e
F = 200N
E equals 5 cm or 5 * 10-2 m
K = 200N/ 5 * 10^-2 m
K = 4000 N/m
Now;
Work = 1/2Ke^2
Work = 0.5 * 4000 N/m * (5 * 10^-2 m)^2
Work = 5 J
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Answer:
If there is a net force acting on an object, the object will have an acceleration and the object's velocity will change. ... Newton's second law states that for a particular force, the acceleration of an object is proportional to the net force and inversely proportional to the mass of the object.
Explanation:
The answer would be a bicycle as it uses both wheels and an axel
Answer:
<em>a) 3344 N</em>
<em>b) 3344 N</em>
Explanation:
This is the complete question
1100 kg car pushes a 2200 kg truck that has a dead battery. When the driver steps on the accelerator, the drive wheels of the car push against the ground with a force of 5000 N. Rolling friction can be neglected. A. What is the magnitude of the force of the car on the truck? Express your answer to two significant figures and include the appropriate units. B. What is the magnitude of the force of the truck on the car?
Mass of the car = 1100 kg
Mass of the truck = 2200 kg
Force exerted on the ground by the car = 5000 N
The total mass in the system = 1100 + 2200 = 3300 Kg
Total force in the system = 5000 N
Recall that the force in the system = mass x acceleration
therefore,
5000 = 3300 x a
Total acceleration in the system = 5000/3300 = 1.52 m/s^2
The force on the truck individually fro the car, will be the product of this acceleration and its mass
Force on the truck = 2200 x 1.52 = <em>3344 N</em>
b) Force on the car From the truck will be equal to this force but will act in the opposite direction.
Force on the car from the truck is <em>3344 N </em>