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noname [10]
3 years ago
12

On Day 16 (in Segment 5), Ebony deposited $100 into her account. On each day after Day 16 (Segment 6) Ebony made a deposit, and

those deposits were equal to each other.
(a) Explain how you can determine, just by looking at the graph, whether the amounts she deposited after Day 16 were each less than, equal to, or greater than $100.
(b) Use the graph to estimate B(21) in hundreds. Explain how you determined this estimate. Then, show how you can estimate the amount of money Ebony deposited into her account each day after Day 16.

Mathematics
1 answer:
Yuliya22 [10]3 years ago
6 0

Answer:Constant 100$

Step-by-step explanation: You can tell because there is constant $100 and where is graph?

NEED GRAPH

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Answer:

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Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let X the random variable that represent the Student scores on exams given by a certain instructor, we know that X have the following distribution:

X \sim N(\mu=74, \sigma=14)

The sampling distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

The deduction is explained below we have this:

E(\bar X)= E(\sum_{i=1}^{n}\frac{x_i}{n})= \sum_{i=1}^n \frac{E(x_i)}{n}= \frac{n\mu}{n}=\mu

Var(\bar X)=Var(\sum_{i=1}^{n}\frac{x_i}{n})= \frac{1}{n^2}\sum_{i=1}^n Var(x_i)

Since the variance for each individual observation is Var(x_i)=\sigma^2 then:

Var(\bar X)=\frac{n \sigma^2}{n^2}=\frac{\sigma}{n}

And then for this special case:

\bar X \sim N(74,\frac{14}{\sqrt{25}}=2.8)

We are interested on this probability:

P(\bar X >80)

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z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

Applying this we have the following result:

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And using the normal standard distribution, Excel or a calculator we find this:

P(Z>2.143)=1-P(z

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