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bazaltina [42]
3 years ago
12

A student is late and running to class. A hall monitor tells them to slow down, so the student slows to a walking speed of 1.4 m

/s. It takes the student 3.0 seconds to slow to this speed, due to the student’s -2.5 m/s2 acceleration. What was the student’s initial speed
Physics
1 answer:
sergey [27]3 years ago
7 0

Answer:

8.9m/s

Explanation:

Final velocity = initial velocity + acceleration *time

Vf=vi+at

Vf=1.4 m/s

Vi=?

A=-2.5m/s^2

T=3

1.4m/s=vi+(-2.5m/s^2)(3s)

Vi=8.9m/s

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Certain neutron stars (extremely dense stars) are believed to be rotating at about 1000 rev/s. If such a star has a radius of 14
Sever21 [200]

Answer:

minimum mass of the neutron star = 1.624 × 10^30 kg

Explanation:

For  a material to remain on the surface of a rapidly rotating neuron star, the magnitude oĺf the gravitational acceleration on the material must be equal to the magnitude of the centripetal acceleration of the rotating neuron star.

This can be represented by the explanations in the attached document.

minimum mass of the neutron star = 1.624 × 10^30 kg

8 0
3 years ago
Two small plastic spheres each have a mass of 1.1 g and a charge of -50.0 nC . They are placed 2.1 cm apart (center to center).
Solnce55 [7]

Answer:

Part a)

F = 0.051 N

Part b)

Both spheres will follow Newton's III law of action reaction force so both sphere will have same force of equal magnitude.

Explanation:

Part a)

Electrostatic force between two charged spherical balls is given as

F = \frac{kq_1q_2}{r^2}

here we will have

q_1 = q_2 = 50 nC

here the distance between the center of two balls is given as

r = 2.1 cm = 0.021 m

now we will have

F = \frac{(9\times 10^9)(50 \times 10^{-9})(50 \times 10^{-9})}{0.021^2}

F = 0.051 N

Part b)

Both spheres will follow Newton's III law of action reaction force so both sphere will have same force of equal magnitude.

3 0
3 years ago
A 100 kg boat is floating in water. half of the boat is submerged under water. what is the weight of the boat?
Alex17521 [72]
W=MG
w is weight 
m is mass
g is gravity 
W=(100 kg)(9.8 m/s)
W= 980 N
hope this helps
7 0
3 years ago
Imagine that you live in Maine. Currently there is a high-pressure area over Maine. If a low-pressure area moves in, how will th
miskamm [114]
I live in maine, windmills
7 0
3 years ago
Steam enters an adiabatic turbine at 5 MPa and 4500C and leaves at a pressure of 1.4 MPa. Determine the work output of the turbi
REY [17]

Answer:350.92 KJ/kg

Explanation:

Given the process is reversible adiabatic i.e it is isentropic

P_1=5 MPa

T_1=4500 MPa

P_2=1.4 MPa

From steam table

h_1=3317.03KJ/kg

For isentropic process s_1=s_2

at P_2=1.4 MPa

s_2=6.82 KJ/kg-k

h_2=2966.11 KJ/kg

Therefore Work output of the turbine per unit mass of steam is =h_1-h_2

=3317.03-2966.11

=350.92 KJ/kg

8 0
3 years ago
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