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3 years ago

The force is the sum of all the forces that act upon an object.

2 answers:

5 0

the forces acting on an object is the net force or resultant force. ... Force is a vector and hence has both a direction and magnitude. For example, gravitational force (on earth) acts in downward direction and has a magnitude equal to mass of the object and acceleration due to gravity.

LUCKY_DIMON [66]3 years ago

3 0

Answer:

Explanation:

The net force or resultant force is sum of all the forces act upon an object. As force is a vector quantity it has both magnitude as well as direction. so net force is calculated by keeping direction of application in mind such as friction force is always acts in the direction opposite to the motion of object and gravitational force always acts downwards.

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A 3.4kg aluminium ball has an apparent mass of 2.10kg when submerged in a particular liquid. Calculate the density of the liquid

Shalnov [3]

Answer:

1083.3kg/m ³

Explanation:

Given parameters:

Mass of aluminium ball = 3.4kg

Apparent mass of ball = 2.1kg

Unknown:

Density of the liquid = ?

Solution:

Density is is the mass per unit volume of any give substance;

Density = $\frac{mass}{volume}$

Now, we must understand that the apparent weight of the aluminium is the part of its weight supported by the fluid;

Pl = $\frac{Ml}{Vl}$

Pl = density of liquid

Ml = mass of liquid

Vl = volume of liquid

Mass of liquid = Mal - Mapparent

Mal = mass of aluminium

The volume of liquid displaced is the same as the volume of the aluminium according to Archimedes's principle;

Ml = Pl x Vl

Val = Vl

Val volume of aluminium

Vl = volume of liquid

****

Pal = $\frac{Mal}{Val}$

Val = $\frac{Mal}{Pal}$

Val = volume of aluminium

Mal = mass of aluminium

Pal = density of aluminium

*****

Since the Val = Vl

Ml = Pl x $\frac{Mal}{Pal}$

Since

Ml = Mal - Mapparent

Mal - Mapparent = Pl x $\frac{Mal}{Pal}$

Pal = density of aluminium = 2712 kg/m ³

3.4 - 2.1 = Pl x $\frac{3.4}{2712}$

1.3 = Pl x 0.00123

Pl = 1083.3kg/m ³

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If my ans was helpful u can follow me.

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