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tia_tia [17]
4 years ago
9

Which energy level requires the most energy to remove an electron?

Chemistry
1 answer:
SOVA2 [1]4 years ago
5 0

Answer:

ionization energy remove an electron

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What is the molar mass of C4H10
Phantasy [73]
Your answer would be 58.12g/mol ;)
7 0
4 years ago
PLEASE HELP ME WITH THIS I WILL GIVE YOU POINTS
eduard

Answer:

1. a

2. c

3. b

4. f

5. d

6. e

Explanation:

7 0
3 years ago
The dissolution of 0.200 l of sulfur dioxide at 19 °c and 745 mmhg in water yields 500.0 ml of aqueous sulfurous acid. The solut
aivan3 [116]

Answer:

Molarity=1.22\ M

Explanation:

Given:  

Pressure = 745 mm Hg

Also, P (mm Hg) = P (atm) / 760

Pressure = 745 / 760 = 0.9803 atm

Temperature = 19 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (19 + 273.15) K = 292.15 K  

Volume = 0.200 L

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9803 atm × 0.200 L = n × 0.0821 L.atm/K.mol × 292.15 K  

⇒n = 0.008174 moles

From the reaction shown below:-

H_2SO_3+2NaOH\rightarrow Na_2SO_3+2H_2O

1 mole of H_2SO_4 react with 2 moles of NaOH

0.008174 mole of H_2SO_4 react with 2*0.008174 moles of NaOH

Moles of NaOH = 0.016348 moles

Volume = 13.4 mL = 0.0134 L ( 1 mL = 0.001 L)

So,

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.016348}{0.0134}\ M

Molarity=1.22\ M

8 0
3 years ago
A liquid-phase isomerization is carried out in a 1000-gal CSTR that has a single impeller located halfway down the reactor. The
igomit [66]

Answer:

The conversion achieved for the first CSTR impeller is 0.382

Discrepancy = 0.188

Explanation:

The impeller divides the CSTR into 2 equal reactors of volume 500gal

Using V = FaoX/ (-ra)

500gal = Fao×Xa/[(KCao^2( 1 -X1)^2]

500gal = CaoVoX1/ KCao^2(1-X1)

500gal= 500gal × X1'/(1 - X1)^2

(1 -X1)^2 = X1

X1^2 - 3X1 + 1 = 0

X1= 0.382

Conversion achieved in the first CSTR is 0.382

Actual measured CSTR = 57% =57/100=0.57

Discrepancy in the conversions= 0.57 -0.383 =0.188

8 0
3 years ago
the men's world record for swimming 1500.0 m in a long course pool (as of 2007) is 14 min 34.56 s. At this rate, how many second
Lyrx [107]

140 s. It would take 140 s to swim 0.150 mi .

<em>Step 1</em>. Convert the <em>time to seconds</em>

Time = 14 min × (60 s/1 min) + 34.56 s = 840 s + 34.56 s = 874.56 s

<em>Step 2</em>. Convert <em>miles to metres </em>

Distance = 0.150 mi × (1609.3 m/1 mi) = 241.4 m

<em>Step 3.</em> Calculate the <em>time to swim 241.4 m</em>

Time = 241.4 m × (874.56 s/1500 m) = 140 s

(<em>As of 2012, the men’s freestyle record for 1500 m was 14:31.02</em>.)

5 0
4 years ago
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