What structures allow small particles to cross the cell membrane

In a heat engine, 700 J of heat enters the system, and the piston does 400 J of work. What is the final internal (thermal) energ

Vitek1552 [10]

The first law of thermodynamics characterises the two types of energy transfer, as heat and as thermodynamic. The final internal (thermal) energy of the system is 1,500 J.

<h3>What is internal energy?</h3>

The energy present in a system itself for conducting reactions is called internal energy.

Given,

Heat entering system (Q) = 700 J
Work done by the piston (W) = 400
Initial energy $(\rm U_{1})$ = 1200 J

According to the <u>first law of thermodynamics</u>:

$\rm Q = \Delta U + W$

Substituting values in the above equation:

$\begin{aligned}\rm Q &= \rm U_{2} - U_{1} + W\\\\\rm U_{2} &= \rm Q - W + U_{1}\\\\\rm U_{2} &= 700 - 400 + 1200\\\\&= 1500 \;\rm J\end{aligned}$

Therefore, option D. 1500 J is the final energy.

Learn more about internal energy here:

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4 0

2 years ago

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Which characteristic might identify a substance as an Arrhenius base?

Scorpion4ik [409]

Answer: a

Explanation: because an Arrhenius acid is a compound that increases the H + ion concentration in aqueous solution. An Arrhenius base is a compound that increases the OH − ion concentration in aqueous solution.

5 0

3 years ago

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Perform the following mathematical operation and report the answer to the appropriate number of significant figures. 5.4-4.21

konstantin123 [22]

Answer:

1.2 ( two significant digits)

Explanation:

5.4 - 4.21 answer should only have the the number of significant digits as the number in the equation with the least number of significant digits... in this case 5.4 is only two significant digits....so the answer should only have two significant digits

5.4 - 4.21 = 1.19 round to two digits = 1.2

3 0

1 year ago

calculate how much acid (acetic acid) and how much conjugate base (sodium acetate) must be used to make 500ml of a 0.8m acetate

kirza4 [7]

For the desired pH of 5.76, 0.365 mol of acetate and 0.035 mol of acid are to be added

let the concentration of acetate be x

then the concentration of acid will be (0.8 - x)

pKa of acetate buffer = 4.76

pH = pKa + log([acetate]/[acid])

⇒4.76 = 4.76 + log(x/(0.8-x))

⇒log(x/(0.8-x)) = 0

⇒x/(0.8-x) = 1

⇒x = 0.4

Therefore

[acetate] = x = 0.4

[acid] = 0.8-x =0.4 M

number of mol = concentration *(volume in mL)

number of mol of acetate = 0.4*0.5

= 0.20 mol

number of mol acid = 0.4*0.5

= 0.20 mol

when desired pH = 5.76

pH = pKa + log([acetate]/[acid])

⇒5.76 = 4.76 + log(x/(0.8-x))

⇒log(x/(0.8-x)) = 1

⇒x/(0.8-x) = 10

⇒x = 8 - 10x

⇒x = 8/11

⇒x= 0.73

[acetate] = x= 0.73

[acid] = 0.8-x = 0.07 M

number of mol = concentration * (volume in mL)

number of mol acetate to be added = 0.73*0.5 = 0.365 mol

number of mol acid to be added = 0.07*0.5 = 0.035 mol

Problem based on acetic acid required to maintain a certain pH

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#SPJ4

4 0

1 year ago

Please help will mark you brainiest! Use word bank when answering the question!

zheka24 [161]

Answer:

Blank 1: varying

Blank 2: constant

Explanation:

7 0

3 years ago