Answer:
liquid oxygen is highly flammable
Explanation:
near any source of heat. liquid oxygen can explode to flames thus being hazardous
Answer:
T2= 7.3°C
Explanation:
To solve this problem we will use Charles law equation i.e,
V1/T1 = V2/T2
Given data
V1 = 269.7 L
T1 = 6.12 °C
V2= 320.4 L
T2=?
Solution:
Now we will put the values in equation
269.7 L / 6.12°C = 320.4 L / T2
T2= 320.4 L × 6.12°C/ 269.7 L
T2= 1960.85 °C. L /269.7 L
T2= 7.3°C
Explanation:
Two events involving electrons are gain and loss of electrons.
When there is gain or loss of electrons between two atoms then it results in the formation of ionic bond.
Whereas when there is sharing of electrons between two atoms then it results in the formation of covalent bond.
Therefore, the chemical bonds formed can be ionic or covalent bonds.
Use blue litmus paper. This is an indicator that can safely determine whether it is a base or an acid by changing color in response to the substance. This color indicates whether it is an acid or a base. Refer to the pH scale to see if the substance is basic or acidic.
Answer:
plzz can you explain in detail this Q
