You have molarity and you have volume. Use the formula :
Molarity(M)= Moles(N)/Liter(L) to get the solution.
150 ml= .150 L
7.7 = N/.150
N=.1.155 moles of NaOH.
And since you know the moles, use the molar mass to figure out the grams.
<span> (40g/mol NaOH) x (1.155mol) =
46.2 g of NaOH.</span>
Answer:
280.8 g
Explanation:
Definimos la reaccion:
2NaOH + FeSO₄ → Na₂SO₄ + Fe(OH)₂
Como tenemos la masa de NaOH, asumimos que el sulfato de hierro (II) es el reactivo en exceso.
Definimos masa de reactivo: 250 g . 1mol / 40g = 6.25 mol
2 moles de NaOH producen 1 mol de hidroxido ferroso
Entonces 6.25 moles producirán, la mitad (6.25 . 1) /2 = 3.125 moles
Convertimos los moles a masa:
3.125 mol . 89.85 g/mol = 280.8 g
Mass of Na2SO4= 514.18 grams
<h3>Further explanation</h3>
Given
423.67 g of NaCl
Required
mass of Na2SO4
Solution
Reaction
2NaCl + H2SO4 → Na2SO4 + 2HCl
mol NaCl :
= 423.67 g : 58.5 g/mol
= 7.24
From the equation, mol Na2SO4 :
= 1/2 x mol NaCl
= 1/2 x 7.24
= 3.62
Mass Na2SO4 :
= 3.62 mol x 142,04 g/mol
= 514.18 grams
Yes it yes molusbus ks jshs jsbjsus js js sjs js sj dis dis jsys snsus
Answer:
The expression of an equilibrium constant will given as:
![K_c=\frac{[NH_3]^2}{[N_2][H_2]^3}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BNH_3%5D%5E2%7D%7B%5BN_2%5D%5BH_2%5D%5E3%7D)
Explanation:
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as 
K is the constant of a certain reaction when it is in equilibrium
The expression of an equilibrium constant will given as:
