Determine which function has a greater initial value and explain how you know.

Mathematics

2 answers:

MA_775_DIABLO [31]3 years ago

8 0

Answer:

Function 2 has a greater initial value

Step-by-step explanation:

An initial value of a function, aka y-intercept, is obtained by using x=0 and evaluating the function at that point. Evaluating the two functions given:

Function1: $y=2x(\frac{1}{3})^x|_{x=0}=2\cdot 0\cdot 1 = 0\\$

Function2 has value 3 for x=0

So, Function 2 has a greater initial value

rosijanka [135]3 years ago

7 0

Answer:

Answer - Function 2

Function 1 - y = 2x (1/3)^x x = 0 =2*0*1 = 0

Function 2 have the value for 3 for x = 0

Function 2 is greater

Step-by-step explanation:

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elena-14-01-66 [18.8K]

Answer:

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Step-by-step explanation:

Using the cosine ratio in the right triangle

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6 0

3 years ago

Please need help.<br><br>find x round to the nearest tenth if necessary.

Dafna11 [192]

Answer:

it's 21 because if you do 7x3 you get =21

4 0

3 years ago

Express in exponential form log(2)16 = 4

S_A_V [24]

$\bf \textit{exponential form of a logarithm}
\\\\
log_a b=y \implies a^y= b\qquad\qquad 
% exponential notation 2nd form
a^y= b\implies log_a b=y \\\\
-------------------------------\\\\
log_2(16)=4\qquad \qquad \implies \qquad 2^4=16$