Determine which function has a greater initial value and explain how you know.
2 answers:
Answer:
Function 2 has a greater initial value
Step-by-step explanation:
An initial value of a function, aka y-intercept, is obtained by using x=0 and evaluating the function at that point. Evaluating the two functions given:
Function1:
Function2 has value 3 for x=0
So, Function 2 has a greater initial value
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Step-by-step explanation:
The parametric equations for the line passes through the points (X₁ , Y₁) and (X₂ , Y₂) are :
X = X₁ + t (X₂ - X₁) ......................... (1)
Y = Y₁ + t (Y₂ - Y₁) .......................... (2)
For eliminating the parameter (t) , first we will solve any one equation for 't' and then substitute that into another equation.
From the equation (1),
⇒ t =
Substituting this t = into the equation (2), we will get :
Y = Y₁ + (Y₂ - Y₁)
Y = Y₁ +
So, this is the standard form of rectangular equation.
For two given points (0, 0) and (4, -4)
X₁ = 0 , Y₁ = 0, X₂ = 4 and Y₂ = -4
For finding the parametric equations, we will plug these values into the given parametric equations.
X = X₁ + t (X₂ - X₁)
⇒ X = 0+ t (4 - 0)
⇒ X = 4t
and Y = Y₁ + t (Y₂ - Y₁)
⇒ Y = 0+ t (-4 - 0)
⇒ Y = - 4t
So, the parametric equations for the line passing through (0,0) and (4, -4) are: X = 4t and Y = -4t
Answer:
<h3>I know they are not the same name but they have the same question they are the same answer</h3>Step-by-step explanation:
<h3>#hope it helps you </h3><h3>#happy learning</h3>