Answer:
Truck= 6.25 m/s
Car= 21.7 m/s
Explanation:
For elastic collision, the truck's final velocity is given by
The car's final velocity is given by
Where m and u denote masses and velocity respectively, subscripts 1 and 2 denote truck and car respectively.
Substituting 1720 Kg for mass of truck, 732 for mass of car and initial velocity as 15.5 m/s
Therefore, the final velocity of truck is 6.25 m/s while the car's final velocity is 21.7 m/s
Answer:
v(t) = 27 units
Explanation:
The function s(t) represents the position of an object at time t moving along a line such that,
and
We need to find the average velocity of the object over the interval of time [2,6]. The velocity of the object is equal to the total distance divided by time. It is given by :
v(t) = 27 units
So, the average velocity of the object is 27 units. Hence, this is the required solution.
Answer:
It will take Andy 1.198minutes to mow the lawn and it will take Brian 1,209.98minutes to mow the same lawn.
Step-by-step explanation:
Using the simultaneous equation concept, let A denote Andy and B be Brian
Andy and Brian can mow the lawn for 1212minutes i.e A+B = 1212..eqn 1
If Brian would mow the lawn by himself in 1010 minutes more than it would take Andy, this means B=1010A...eqn 2.
Substituting eqn 2 into eqn 1
Equation 1 becomes
A+1010A=1212
1011A=1212
A=1212/1011
A=1.198
B = 1010×1.198
B=1,209.98
Therefore, It will take Andy 1.198minutes to mow the lawn and it will take Brian 1,209.98minutes to mow the same lawn.
Answer:
0.12m/s
Explanation:
v=λf
Given that, λ = 12cm = 0.12m
T = 1second
(A period T is the time required for one complete cycle of vibration to pass a given point)
frequency 'f' is unknown but we can get frequency from f = 1/T = 1/1 = 1Hz
therefore, v= 0.12 × 1 = 0.12m/s
The answer for the problem is explained through this:
The following are the given:
F = 4.719 N, the applied force
a = 33 m/s², the acceleration
Let m = the mass.
By definition of the formula:
F = m*a
Therefore,
m = F/a
= (4.719 N)/(33 m/s²)
= 0.143 kg
Answer: 0.143 kg