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saw5 [17]
2 years ago
11

Isotopes are atoms with identical numbers of __ and different numbers of __.

Physics
1 answer:
Tju [1.3M]2 years ago
4 0
D. Protons; neutrons
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I need to submit my homework in an hour, this is only question i cant solve. someone pls help!!
Sauron [17]

Hope this helps.......☺

8 0
3 years ago
For installation with a 25-kVA, 3-phase transformer, a 440-volt primary, and a 120-volt secondary. Calculate the maximum overcur
andre [41]

Answer:

41.053 A

Explanation:

given,

three phase kVA = 25-kVA

voltage = 440 Volt

current = ?

To determine three phase kVA when volts and amperes are know

   three phase kVA = 1.73 x V x I

    I = \dfrac{three\ phase\ kVA}{1.73 \times V}

    I = \dfrac{25000}{1.73 \times 440}

           I = 32.84 A

the maximum overcurrent protection value is equal to

            = 125 % of I

            = 1.25 x 32.84

            = 41.053 A

4 0
3 years ago
If you quadruple the temperature of a black body, by what factor will the total energy radiated per second per square meter incr
arlik [135]

<u>In modern physics</u>, as it was called "Stefan-Boltzmann law", the total energy radiated per unit surface area of a black body is directly proportional to the fourth power of the black body's temperature T

as:

P\alpha T^4

where: P is the power (total energy radiated per second per square meter) and T is the temperature of a black body.

then we can make a ratio between the state of before quadruple (with subscript 1) and after (with subscript 2) as:

\frac{P_{1} }{P_{2} } =\frac{T_{1}^4 }{T_{2}^4}

As

T_{2}=4T_{1}

Then

\frac{P_{1} }{P_{2} } =\frac{T_{1}^4 }{(4T_{1})^4}

then

P_{2}=256*P_{1}

  • The factor will the total energy radiated per second per square meter increase = 256
5 0
3 years ago
What are the relative ages of the features in order of oldest to youngest?
yuradex [85]

Answer:

Layer 1, Rock 2, Rock 1, Fault

8 0
2 years ago
A 1500 kg car traveling 5.0 m/s collides head on with a 3000 kg truck traveling
Setler [38]
  • m1=1500kg
  • m_2=3000kg
  • v_1=5m/s
  • v_2=7m/s

Using law of conservation of momentum

\\ \sf\Rrightarrow m_1v_1-m_2v_2=(m1+m2)v_3

\\ \sf\Rrightarrow 1500(5)-3000(7)=(1500+3000)v_3

\\ \sf\Rrightarrow 7500-21000=4500v_3

\\ \sf\Rrightarrow -13500=4500v_3

\\ \sf\Rrightarrow v_3=-3m/s

6 0
2 years ago
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