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Lesechka [4]
2 years ago
15

Ts to

Physics
1 answer:
Leni [432]2 years ago
5 0

The charge not experience a net magnetic force if it moves to the right.

<h3>What is the magnetic force?</h3>

The magnetic force is a force that is felt by an object owing to the presence of a magnet. We should note that when a charge is placed in a magnetic field, it experiences a magnetic force.

The direction in which the charge will experience no net magnetic force is when the charge moves towards the right.

Learn more about magnetic field:brainly.com/question/3673512

#SPJ1

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We all have a tendency to make illusory correlations from time to time. Try to think of an illusory correlation that is held by
Artist 52 [7]

Answer:

Thats a personal question

Explanation:

It asks about you

(illusion is something you think is there but is not)

5 0
2 years ago
a certain car travels 20 km east then turns south for 13 km finally the car turns east again for 6 km
aliya0001 [1]

a^2+b^2=c^2

20km^2+13km^2=c^2

400km^2+169km^2=c^2

23.853720...km

7 0
3 years ago
Read 2 more answers
Two 10-cm-diameter charged rings face each other, 21.0 cm apart. Both rings are charged to +40.0 nC. What is the electric field
Katyanochek1 [597]

Complete question:

Two 10-cm-diameter charged rings face each other, 21.0 cm apart. Both rings are charged to +40.0 nC. What is the electric field strength  at the midpoint between the two rings ?

Answer:

The electric field strength at the mid-point between the two rings is zero.

Explanation:

Given;

diameter of each ring, d = 10 cm = 0.1 m

distance between the rings, r = 21.0 cm = 0.21 m

charge of each ring, q = 40 nC = 40 x 10⁻⁹ C

let the midpoint between the two rings = x

The electric field strength  at the midpoint between the two rings is given as;

E_{mid} = E_{right} +E_{left}\\\\E_{right}  = \frac{KQ}{(x^2 + r^2)^\frac{2}{3} } \\\\E_{leftt}  = -\ \frac{KQ}{(x^2 + r^2)^\frac{2}{3} }\\\\E_{mid} = \frac{KQ}{(x^2 + r^2)^\frac{2}{3} }  - \frac{KQ}{(x^2 + r^2)^\frac{2}{3} } = 0

Therefore, the electric field strength at the mid-point between the two rings is zero.

7 0
3 years ago
When potential energy ___________ , kinetic energy increases.
BARSIC [14]

When potential energy <u>decreases</u>, kinetic energy increases.

5 0
3 years ago
Read 2 more answers
A light, a heater, and a hair dryer were all running in the bathroom at the same time. Suddenly, they all turn off. After all, t
Ratling [72]
Well depending on what current the heater pulls im going to assume about 13, and 13A for the hair dryer, thats 26A on the 40A circuit.
I dont see how a lightbulb could overload the circuit. 

Anyway, assuming the circuit is overloaded by some really big heater- the circuit would trip, the fuse would go and remain off. Most houses are fitted with seperate circuits for lights and sockets, so the light may remain on depending on the breaker board. - the reason for them all being able to run with the sudden overload may be due to a surge.

One solution to this is not to put such a large heater on the circuit with other appliances. 

Another may be to dry your hair in the dark
3 0
3 years ago
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