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sergejj [24]
3 years ago
11

You are told that in a billiards shot, the cue ball was shot at the eight ball, which was 8 inches away. As a result, the eight

ball rolled into a pocket, which was 6 inches away. Knowing that the angle made with the path of the cue ball and the resulting path of the eight ball is larger than 90°, it can be determined that the original distance from the cue ball to the pocket was greater than inches.
Mathematics
2 answers:
mixer [17]3 years ago
7 0
Just did it on edgueinty its 10 inches :)
Trava [24]3 years ago
5 0
The answer is ten inches 
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vekshin1

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8 0
2 years ago
|y-9|=6<br><br><br>a. y=-15, y=-3<br><br>b. y=-15, y=15<br><br>c. y=3, y=15<br><br>d.y=-3, y=3
ELEN [110]
I hope you get it.
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3 years ago
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crimeas [40]

Step-by-step explanation:

i) \overline{AB} = \sqrt{(x_A - x_B)^2 + (y_A - y_B)^2}

\:\:\:\:\:\:\:=\sqrt{(2)^2 + (12)^2} = 12.3

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iii) (\overline{x},\:\overline{y}) = \left(\dfrac{x_A + x_B}{2},\:\dfrac{y_A + y_B}{2}\right)

\:\:\:\:\:\:\:=(3,\:-2)

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