|r+3| = (r+3) when r ≥ -3 so for r ≥ -3
r + 3 ≥ 7
r ≥ 4
|r+3| = -(r+3) when r < -3 so for r < -3
-(r + 3) ≥ 7
r + 3 ≤ -7
r ≤ -10
The answer to this question is r ≤ -10, r ≥ 4
Linear, decrease by 2 for every decrease of x.
Answer:
due to not much information given and the way you ask the question I would definitely say no
The answer is D. -15 because I am assuming that the vertical lines mean brackets, and we have to work out the brackets first (according to BIDMAS). Doing so, -6 + 2 = -4 and -4 + -11 = -15.
Answer:
The area of the paralellogram is 24 square units.
Step-by-step explanation:
Geometrically speaking, the area of the parallelogram has an equation equivalent to the area formula for a rectangle, that is:
(1)
Where:
- Area.
- Base.
- Height.
The base and height of the parallelogram are, respectively:
Base


Height


Then, the area of the parallelogram is:


The area of the paralellogram is 24 square units.