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2 years ago

if 150g of aluminum react with 101g of sulfuric acid what is the maximum amount of hydrogen gas that can be produced

1 answer:

4 0

2Al + 3H2SO4 -> 3H2 + Al2(SO4)3

First, find your limiting reactant - do this with your moles.

Have:
Al - 5.559mol
H2SO4 - 1.030mol
Need:
Al - 0.6867mol
H2SO4 - 8.339mol

Your limiting reactant is sulfuric acid, so we will use that.

Use your mole bridge and the calculated HAVE of sulfuric acid to do this.

1.030mol * (3/3) = 1.030mol of H2

If you want it in liters, multiply that by 22.4dm^3. If you want it in grams, multiply it by 2.016. Hope this helps!

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An electrochemical cell has the following standard cell notation.

icang [17]

The cell notation is:

$Mg(s)|Mg^{+2}(aq)||Ag^{+}(aq)|Ag(s)$

here in cell notation the left side represent the anodic half cell where right side represents the cathodic half cell

in anodic half cell : oxidation takes place [loss of electrons]

in cathodic half cell: reduction takes place [gain of electrons]

1) this is a galvanic cell

2) the standard potential of cell will be obtained by subtracting the standard reduction potential of anode from cathode

$E^{0}_{Mg}=-2.38V$

$E^{0}_{Ag}=+0.80V$

Therefore

$E^{0}_{cell}=0.80-(-2.38)=+3.18V$

3) as the value of emf is positive the reaction will be spontaneous as the free energy change of reaction will be negative

Δ $G^{0}=-nFE^{0}$

As reaction is spontaneous and there will be conversion of chemical energy to electrical energy it is a galvanic cell.

7 0

2 years ago

You can practice converting between the mass of a solution and mass of solute when the mass percent concentration of a solution

LUCKY_DIMON [66]

Answer: The mass of solution having 768 mg of KCN is 426.66 grams.

Explanation:

We are given:

0.180 mass % of KCN solution.

0.180 %(m/m) KCN solution means that 0.180 grams of KCN is present in 100 gram of solution.

To calculate the mass of solution having 768 mg of KCN or 0.786 g of KCN (Conversion factor: 1 g = 1000 mg)

Using unitary method:

If 0.180 grams of KCN is present in 100 g of solution.

So, 0.768 grams of KCN will be present in = $\frac{100g}{0.180g}\times 0.768=426.66g$ of solution.

Hence, the mass of solution having 768 mg of KCN is 426.66 grams.

8 0

3 years ago

In order to have a contact force acting on an object, the force

Oliga [24]

I believe the answer is C. (must be touching the object)

Someone please correct me if I am wrong.

5 0

3 years ago

The reaction of ethane gas (C2H6) with chlorine gas produces C2H5Cl as its main product (along with HCl). In addition, the react

Kazeer [188]

Answer:

The percent yield of chloro-ethane in the reaction is 82.98%.

Explanation:

$C_2H_6+Cl_2\rightarrow C_2H_5Cl+HCl$

Moles of ethane = $\frac{300.0 g}{30 g/mol}=10 mol$

Moles of chlorine gases = $\frac{650.0 g}{71 .0 g/mol}=9.1549 mol$

As we can see that 1 mol of ethane react with 1 mole of chlorine gas.the 10 moles will require 10 mole of chlorine gas, but only 9.1549 moles of chlorine gas is present.

This means that chlorine gas is in limiting amount and amount of formation of chloro-ethane will depend upon amount of chlorine gas.

According to reaction , 1 mol of chloro ethane gives 1 mol of chloro-ethane.

Then 9.1549 moles of chlorien gas will give:

$\frac{1}{1}\times 9.1549 mol=9.1549 mol$ of chloro-ethane

Mass of 9.1549 moles of chloro-ethane:

9.1549 mol × 64.5 g/mol = 590.4910 g

Theoretical yield of chloro-ethane: 590.4910 g

Given experimental yield of chloro-ethane: 490.0 g

$\% Yield=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

$\%Yield (C_2H_5Cl)=\frac{490.0 g}{590.4910 g}\times 100=82.98\%$

The percent yield of chloro-ethane in the reaction is 82.98%.

6 0

2 years ago

If the solvent front is 68 mm and the ring front of an unknown is 48mm from the original spot, what is the rf value?

Nat2105 [25]

Given:

Distance of solvent front = 68 mm

Distance of unknown = 48 mm

To determine:

The rf value

Explanation:

The retention factor or the rf value is given by the ratio of distance traveled by the unknown to the distance traveled by the solvent front

RF = distance by unknown/distance by solvent

RF = 48/68 = 0.706

Ans: the RF value is 0.706

3 0

2 years ago