Answer:
Option 4
Explanation:
Hydrochloric acid is a strong one, that gives protons to medium. It can be dissociated as this:
HCl → H⁺ + Cl⁻
M means Molarity. It is a sort of concentration that indicates the moles of solute in 1L of solution.
M = moles / volume (L)
We can also say M = mmoles / mL of solution
M . mL = mmoles
0.453 M . 62.85mL = 28.5 mmoles
If we divide by 1000 → 28.5 mmol . 1 mol / 1000 mmol = 0.0285
Answer:
a. 2nd order reaction.
b. The first step is the slow step.
Explanation:
r = k[NO][Cl₂]
a. The reaction is first-order in [NO] and first-order in [Cl₂], so it is second-order overall.
b. The first step is the slow step, because it predicts the correct rate law.
c. is wrong. Doubling [NO] would double the rate, because the reaction is first-order in [NO].
d. is wrong. Cutting [Cl₂] in half would halve the rate, because the reaction is first-order in [Cl₂].
e. is wrong. The molecularity is two, because two particles are colliding.
f. is wrong. Both steps are bimolecular.
Answer:
The answer is "10.84 g".
Explanation:
The formula for calculating the number for moles:

In the given acid nitric:
Owing to the nitric acid mass = 
Nitric acid molar weight
If they put values above the formula, they receive:


In the given chemical equation:

In this reaction, 2 mols of nitric acid are produced by 1 mole of water.
So, 1.204 moles of nitric acid will be produced:

We are now using Equation 1 in determining the quantity of water:
Water moles 
Water weight molar 


When pressure in a chemical reaction increases, the equilibrium will shift towards the side of the reaction with fewer moles of gas. When there is a decrease in pressure, the equilibrium will shift towards the side of the reaction with more moles of gas.Therefore; in this case; increased the Equilibrium will shift to the left and favor the reverse reaction. This is because the side of products has more moles compared to the side of reactants, thus increased in pressure will aid conversion of products to reactants.
At a definite amount of solute and at a definite tempreture it is dissolved in utane above that it remain unsoluble