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2 years ago

12

You add 8.5 g of iron to 27.90 mLof water and observe that the volume of iron and water together is 28.98 mL calculate the densi

ty of iron

1 answer:

Verdich [7]2 years ago

3 0

Answer: 7.87 g/ml

Explanation:

(28.98 ml - 27.90ml) = 7.87 g/ml

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Which of these solutes raises the boiling point of water the most?

sergey [27]

Answer:

D. ionic sodium phosphate (Na3PO4)

Explanation:

Molecule for molecule, the solute that raises the boiling point of water the most is the one that makes the most particles in the solution. Lithium chloride breaks up into two ions (Li+ and Cl-). So does sodium chloride (Na+ and Cl-). Molecular molecules don't break up at all, so sucrose has only 1 particle per molecule. Sodium phosphate makes 4 total particles (3 Na+ ions and 1 PO4^3-). And magnesium bromide would make 3 particles (1 Mg2+ and 2 Br-). So the most is 4.

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3 years ago

What are some sources of non-point source water pollution?

kirza4 [7]

Answer:

Explanation:

Excess fertilizers, herbicides and insecticides from agricultural lands and residential areas.

Oil, grease and toxic chemicals from urban runoff and energy production.

Sediment from improperly managed construction sites, crop and forest lands, and eroding streambanks.

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3 years ago

Read 2 more answers

When 231. mg of a certain molecular compound X are dissolved in 65. g of benzene (CH), the freezing point of the solution is mea

Elan Coil [88]

Answer:

Molar mass X = 18.2 g/mol

Explanation:

Step 1: Data given

Mass of compound X = 231 mg = 0.231 grams

Mass of benzene = 65.0 grams

The freezing point of the solution is measured to be 4.5 °C.

Freezing point of pure benzene = 5.5 °C

The freezing point constant for benzene is 5.12 °C/m

Step 2: Calculate molality

ΔT = i*Kf*m

⇒ΔT = the freezing point depression = 5.5 °C - 4.5 °C = 1.0 °C

⇒i = the Van't hoff factor = 1

⇒Kf = the freezing point depression constant for benzene = 5.12 °C/m

⇒m = the molality = moles X / mass benzene

m = 1.0 / 5.12 °C/m

m = 0.1953 molal

Step 3: Calculate moles X

Moles X = molality * mass benzene

Moles X = 0.1953 molal * 0.065 kg

Moles X = 0.0127 moles

Step 4: Calculate molar mass X

Molar mass X = mass / moles

Molar mass X = 0.231 grams / 0.0127 moles

Molar mass X = 18.2 g/mol

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3 years ago

To make a smore, 2 graham crackers, a piece of chocolate, and a marshmallow are needed. You have 5 graham crackers, 7 pieces of

vfiekz [6]

Limiting Reactant - The reactant in a Chemical Reaction that limits the amount of product that can be formed.

Excess Reactant - The reactant in a chemical reaction that remains when a reaction stops when the limiting reactant is completely consumed.

Theoretical Yield - The quantity of a product obtained from the complete conversion of the limiting reactant in a Chemical reaction.

I hope this helped make your question easier ^_^

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3 years ago

Read 2 more answers

Calculate: A. Mercury has a specific Heat Capacity of 0.14 J/goC. How much heat is needed to raise the thermometer temperature 1

kari74 [83]

Answer:

$\boxed {\boxed {\sf 56 \ Joules}}$

Explanation:

We are given the mass, specific heat, and temperature, so we must use this formula for heat energy.

$q=mc \Delta T$

The mass is 5 grams, the specific heat capacity is 0.14 Joules per gram degree Celsius. Let's find the change in temperature.

ΔT= final temperature - initial temperature
ΔT= 95°C - 15°C = 80°C

We know the variables and can substitute them into the formula.

$m= 5 \ g \\c= 0.14 \ J/ g \ \textdegree C \\\Delta T= 80 \ \textdegree C$

$q= (5 \ g )( 0.14 \ J/ g \ \textdegree C ) ( 80 \ \textdegree C)$

Multiply the first numbers. The grams will cancel.

$q= 0.7 \ J/ \textdegree C(80 \ \textdegree C )$

Multiply again. This time the degrees Celsius cancel.

$q= 56 \ J$

56 Joules of heat are needed.

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2 years ago