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3 years ago

Name the element that has atom with 4 proton in the nucleus

Chemistry

2 answers:

QveST [7]3 years ago

6 0

The element with 4 protons in the nucleus in Beryllium.

Eduardwww [97]3 years ago

5 0

Answer:

beryllium atom

Explanation:

An atom with two protons is always a helium atom. If scientists count four protons in an atom, they know it's a beryllium atom.

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Answer:

Explanation:

6. Where on the graph does adding heat energy NOT raise the temperature?

What is the heat energy DOING if it's not raising the temperature? :its being compressed I believe its vaporizing

7. What is temperature A called? Freezing

8. What is temperature B called? Vaporizing

4 0

3 years ago

NaF + HCL=> NACL + HF

Jobisdone [24]

Answer:

NaF + HCl --> NaCl + HF

Explanation:

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2 years ago

The air pressure inside a submarine is 0.832atm. What would the pressure be in mnhg

Gwar [14]

Answer:

632.32 mmHg

Explanation:

Millimetre mercury:

It is the monometric unit of pressure. It is define as "The pressure exerted by the column pf mercury at the height of 1 millimetre.

It is represented as mmHg.

It can also be written as mm Hg.

Atmosphere (atm):

It is barometric pressure, define as "The force exerted by atmospheric column on per unit area".

It is written as "atm".

Conversion of atm to mmHg:

0.832 atm × 760 mmHg / 1 atm

632.32 mmHg

5 0

3 years ago

How viscosity affects the speed of the liquid in the convection cell.

Fed [463]

Explanation:

eggsus8d8ruttuririiryrey

6 0

2 years ago

The mass percent of carbon in a typical human is 18%, and the mass percent of 14C in natural carbon is 1.6 × 10-10%. Assuming a

Tema [17]

Answer:

4066 decay/s

Explanation:

Given that:-

The weight of the person is:- 190 lb

Also, 1 lb = 453.592 g

So, weight of the person = 86182.6 g

Also, given that carbon is 18% in the human body. So,

$\%\ Carbon=\frac{18}{100}\times 86182.6\ g=15512.868\ g$

Carbon-14 is $1.6\times 10^{-10}\ \%$ of the carbon in the body. So,

$\%\ Carbon-14=\frac{1.6\times 10^{-10}}{100}\times 15512.868\ g=2.48\times 10^{-8}\ g$

Also,

14 g of Carbon-14 contains $6.023\times 10^{23}$ atoms of carbon-14

So,

$2.48\times 10^{-8}\ g$ of Carbon-14 contains $\frac{6.023\times 10^{23}}{14}\times 2.48\times 10^{-8}$ atoms of carbon-14

Atoms of carbon-14 = $1.07\times 10^{15}$

Given that:

Half life = 5730 years

$t_{1/2}=\frac {ln\ 2}{k}$

Where, k is rate constant

So,

$k=\frac {ln\ 2}{t_{1/2}}$

$k=\frac{ln\ 2}{5730}\ years^{-1}$

The rate constant, k = 0.00012 years⁻¹

Also, 1 year = $3.154\times 10^7$ s

So, The rate constant, k = $\frac{0.00012}{3.154\times 10^7}$ s⁻¹ = $3.8\times 10^{-12}\ s^{-1}$

Thus, decay events per second = $K\times atoms decayed$ = $3.8\times 10^{-12}\times 1.07\times 10^{15}\ decay/s$ = 4066 decay/s

4 0

3 years ago