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3 years ago

Which of the following box-and-whisker plots correctly displays the data set?

Mathematics

1 answer:

Tems11 [23]3 years ago

8 0

The answer is C. the max and min are 20 and 11 which are only graphed in choice c

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Scientists in Florida are measuring the masses of sea turtles as they hatch. They create a line graph and plots the masses of 18

NeTakaya

Answer:

36 3/4

Step-by-step explanation:

12 1/4 + 12 1/4 + 12 1/4 = 36 3/4 :)

8 0

3 years ago

A plane flies 1640 miles in 4 hours. what is the average speed of the plane?

Lina20 [59]

The answer to that question would be 410 miles per hour

8 0

3 years ago

Read 2 more answers

Which equation has a graph that passes through the points at (0,5) and (-3,-4)?

Roman55 [17]

Answer:

$y = 3x + 5$

Step-by-step explanation:

We are asked the equation of the graph which passes through the points at (0,5) and (-3,-4).

Now, we know that the equation of a straight line passing through the points ( $x_{1},y_{1}$ ) and ( $x_{2},y_{2}$ ) is given by

$\frac{y - y_{1}}{y_{1} - y_{2}} = \frac{x - x_{1}}{x_{1} - x_{2}}$ .

So, in our case ( $x_{1},y_{1}$ ) ≡ (0,5) and ( $x_{2},y_{2}$ ) ≡ (-3,-4)

Therefore, the equation of the straight line will be

$\frac{y - 5}{5 - (- 4)} = \frac{x - 0}{0 - (- 3)}$

⇒ $y - 5 = \frac{9}{3}x$

⇒ $y = 3x + 5$ (Answer)

4 0

3 years ago

Which are true statements about a translation?

jeka94

a} The image is congruent to the pre-image.

c} The image could be moved left or right.

d} The image could be moved up or down.

6 0

2 years ago

Find the area ratio of a regular octahedron and a tetrahedron regular, knowing that the diagonal of the octahedron is equal to h

Anton [14]

Answer:

$\frac{4}{3}$

Step-by-step explanation:

The area of a regular octahedron is given by:

area = $2\sqrt{3}\ *edge^2$ . Let a is the length of the edge (diagonal).

area = $2\sqrt{3}\ *a^2$

Given that the diagonal of the octahedron is equal to height (h) of the tetrahedron i.e.

a = h, where h is the height of the tetrahedron and a is the diagonal of the octahedron. Let the edge of the tetrrahedron be e. To find the edge of the tetrahedron, we use:

$h=\sqrt{\frac{2}{3} } e\\but\ h=a\\a=\sqrt{\frac{2}{3} } e\\e=\sqrt{\frac{3}{2} }a$

The area of a tetrahedron is given by:

area = $\sqrt{3}\ *edge^2$ = $\sqrt{3} *(\sqrt{\frac{3}{2} }a)^2=\frac{3}{2}\sqrt{3} *a^2$

The ratio of area of regular octahedron to area tetrahedron regular is given as:

Ratio = $\frac{2\sqrt{3}\ *a^2}{\frac{3}{2} \sqrt{3}*a^2} =\frac{4}{3}$

7 0

3 years ago