(y+1/x)^(x+y)*(x-1/y)^(x+y)÷{(x^2-1/y^2)^x*(y^2-1/x^2)^y}
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Answer:
As x —> negative infinity, f(x) —> negative infinity
As x —> positive infinity, f(x) —> positive infinity.
Step-by-step explanation:
An odd-degree function, meaning that the graph starts from negative infinity at x —> negative infinity and positive infinity at x —> positive infinity.
As x —> negative infinity, f(x) —> negative infinity
As x —> positive infinity, f(x) —> positive infinity.
An odd-degree function is an one-to-one function so whenever x approaches positive, f(x) will also approach positive.
The confidence interval for the mean usage of water is (18.7,20.5).
Given population standard deviation of 2.4, mean of 19.5 gallons per day and confidence interval of 98%.
We have to find the confidence interval for the mean usage of water.
To find out the confidence interval we have to first find margin of error.
μ=19.5
σ=2.4
α=0.98
α/2=0.49
We have to find the z value for the p value 0.49 which is z=2.33
Margin of error=z*μ/
=2.33*19.5/
=0.82
lower level=mean -m
=19.5-0.82
=18.68
after rounding upto 1 decimal
=18.7
upper mean = mean+m
=19.5+0.82
=20.52
Hence the confidence interval for the usage of water is (18.7,20.52).
Learn more about margin of error at brainly.com/question/10218601
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Consider this option:
Volume is 256π/5, area is 32/3.
Details are in the attachment.
P.S. intersection points are (-2;4) and (2;4).
Volume is 256π/5, area is 32/3.
Details are in the attachment.
P.S. intersection points are (-2;4) and (2;4).