Mass = 39.0 gal × (3.785 L/1 gal) × (1000 mL/1 L) × (0.789 g/1 mL) × (1 lb/453.6 g) = 257 lb
Answer:
CF4 is non polar
polar, no net, nonpolar
Explanation:
The overall polarity of a molecule depends on the presence of polar bonds within the molecule and the orientation of the polar bonds to produce an overall dipole moment. This implies that the presence of polar bonds in a molecule does not automatically imply that such molecule is polar or will display on overall dipole moment. The orientation of the individual dipoles affects the overall dipole moment of the molecule.
A polar molecule results from an unequal/unsymmetrical sharing of valence electrons. While there may be unequal sharing of electrons in the individual bonds, in a nonpolar molecule like CF4 these bonds are evenly distributed and cancel out. There is no net dipole and the CF4 is non-polar. Hence the order of words chosen in the answer to fill in the blanks.
The heat released by reaction : C) -8870 J
<h3>Further explanation</h3>
Given
1.008 g of hydrogen
500.00 g water
The temperature rises 25.00 °C to 29.24 °C
Required
energy required
Solution
Q absorbed by water :
Q = m.c.Δt
Q = 500 g x 4.18 J/g C x (29.24-25)
Q = 8870.08 J
The reaction to produce HCl is an exothermic reaction (releasing heat), so that Q is negative
Q water = -Q HCl = -8870.08 J
Answer:
37.5 mL of a 4.0 M Mg(OH)₂ are needed to make 750 mL of 0.2 M Mg(OH)₂
Explanation:
Dilution is the reduction in concentration of a chemical in a solution. Dilution consists of lowering the amount of solute per unit volume of solution.
In other words, dilution is the procedure followed to prepare a less concentrated solution from a more concentrated one, and consists of adding solvent to an existing solution. The quantity or mass of the solute is not changed but only that of the solvent.
In dilutions the expression is used:
Ci*Vi = Cf*Vf
where:
- Ci: initial concentration
- Vi: initial volume
- Cf: final concentration
- Vf: final volume
In this case:
- Ci: 4 M
- Vi: ?
- Cf: 0.2 M
- Vf: 750 mL
Replacing:
4 M* Vi= 0.2 M* 750 mL
Solving:
Vi= 37.5 mL
<u><em>37.5 mL of a 4.0 M Mg(OH)₂ are needed to make 750 mL of 0.2 M Mg(OH)₂</em></u>
