Mass number...use da textbook bra
Answer:
106.25 mL
Explanation:
For this, we can use
C1×V1=C2×V2
C1 = 0.45
V1 = 85
C2= 0.20
V2= ?
0.45 × 85 = 0.20 × V2
V2= (0.45 × 85)/0.20
V2=191.25mL
To find the amount of water added, subtract V1 from V2
191.25 - 85 =106.25mL
Answer:
The answer is 37amu
Explanation:
We are given:
Chlorine-35: atomic mass =35 amu and percent abundance =75.5% ≡ 0.755
Chlorine-37: atomic mass = x amu and percent abundance =24.5% ≡ 0.25
From table, relative atomic mass of Chlorine is 35.5
⇒(0.755 × 35) + (24.5 × x) = 35.5
26.402 + 24.5x = 35.5
∴ x = 9.075 ÷ 24.5 = 0.37 ≡ 37.
∴ mass of Chlorine 37 = 37amu
Scientist rely on their estimates when they cannot obtain on exact numbers
Answer:
6.022×1023 individual items of that something. You have 3 moles, so there are 3×6.022×1023 oxygen molecules
Explanation:
6.022×1023 individual items of that something. You have 3 moles, so there are 3×6.022×1023 oxygen molecules
