Answer:
93.5 kPa
Explanation:
Step 1: Given data
- Initial pressure (P₁): 81.0 kPa
- Initial temperature (T₁): 50 °C
- Final volume (T₂): 100 °C
Step 2: Convert the temperatures to the Kelvin scale
When working with gases, we need to consider the absolute temperature. We will convert from Celsius to Kelvin using the following expression.
K = °C + 273.15
T₁: K = 50°C + 273.15 = 323 K
T₂: K = 100°C + 275.15 = 373 K
Step 3: Calculate the final pressure of the gas
At a constant volume, we can calculate the final pressure of the gas using Gay-Lussac's law.
P₁/T₁ = P₂/T₂
P₂ = P₁ × T₂/T₁
P₂ = 81.0 kPa × 373 K/323 K
P₂ = 93.5 kPa
Answer:
#1 is protons electrons and neutrons
their respective parts are center, positive ,and no charge
#2 is positive charge, chemical properties
#3 is the number of protons, characteristics, same
#4 is atomic mass, average atomic mass
#5 is mass number, nucleus
Explanation:
no need to say thank tou i know ur in class
Answer:
Volume = 3.86 ml (Approx)
Explanation:
Given:
Density of cadmium = 8.65 g/ml
Mass of pure object = 33.4 g
Find:
Volume pure cadmium
Computation:
Volume = Mass / Density
Volume = 33.4 / 8.65
Volume = 3.86 ml (Approx)
Answer:
There are other details missing in the question. i.e Assume that x is much larger than the separation d between the charges in the dipole, so that the approximate expression for the electric field along the dipole axis E = p/2πε0y3 can be used, where p is the dipole moment, and y is the distance between ions. A) What is magnitude______N B) Direction? +x-direction or -x-direction C) Is this force attractive or repulsive?
A) Magnitude of electric force = 6.576 x 10 raised to power -13 N
B) Since the force direction is always dependent on the electric field and electric field = F/q, since the chlorine has a negative charge as such the direction of the electric force will be in the X - direction
C) Since the charges are of different nature, as such the force between them will be ATTRACTIVE.
Explanation:
The detailed steps is shown in the attachment
Answer:
0.6 moles of CaO will produced.
Explanation:
Given data:
Mass of calcium = 23.9 g
Moles of CaO produced = ?
Solution:
Chemical equation:
2Ca + O₂ → 2CaO
Number of moles of calcium:
Number of moles = mass/ molar mass
Number of moles = 23.9 g / 40 g/mol
Number of moles = 0.6 mol
Now we will compare the moles of calcium and CaO.
Ca : CaO
2 : 2
0.6 : 0.6
0.6 moles of CaO will produced.
