The options for given question are as follow,
1) Methane molecules show hydrogen bonding.
<span>2) Ammonia molecules show hydrogen bonding. </span>
<span>3) Methane has stronger hydrogen bonding than ammonia. </span>
<span>4) Both the compounds do not show hydrogen bonding. </span>
<span>5) Both the compounds have strong hydrogen bonding.
</span>
Answer:
Correct answer is Option-2 (Ammonia molecules show hydrogen bonding).
Explanation:
Hydrogen bond interactions are formed when a partial positive hydrogen atom attached to most electronegative atom of one molecule interacts with the partial negative most electronegative element of another molecule. So, in Ammonia hydrogen gets partial positive charge as nitrogen is highly electronegative. While the C-H bond in Methane is non-polar and fails to form hydrogen bond interactions.
The molarity of the ammonia solution is 1.38 M
<h3>Definition of molarity</h3>
Molarity is defined as the mole of solute per unit litre of the solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
<h3>Determination of the mole of NH₃</h3>
•Mass of NH₃ = 23.5 g
•Molar mass of NH₃ = 14 + (3×1) = 17 g/mol
•Mole of NH₃ =?
Mole = mass / molar mass
Mole of NH₃ = 23.5 / 17
Mole of NH₃ = 1.38 mole
<h3>Determination of the molarity </h3>
•Mole of NH₃ = 1.38 mole
•Volume = 1 L
•Molarity of NH₃ =?
Molarity = mole / Volume
Molarity of NH₃ = 1.38 / 1
Molarity of NH₃ = 1.38 M
Learn more about molarity:
brainly.com/question/9468209
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M[(NH₄)₂SO₄]=2A(N)+8A(H)+A(S)+4A(O)
M[(NH₄)₂SO₄]=2·14.0+8·1.0+32.1+4·16.0=132.1 g/mol
Answer:
The temperature at which the vapor pressure of a liquid is just equal to the external ... The conversion of a liquid to a gas below the boiling point is called ... equilibrium temperature of the mixture was 36.0 °C. What is the specific heat (J/ g°C) of the metal
Explanation:
You should use a graduated cylinder or a beaker