* The measurement for volume is? O grams O liters Oatom O mole
1 answer:
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Answer:
<em>Three (3) of the molecules are polar: </em><em> </em>
<em> </em>
<em>.</em>
Explanation:
Polar substances have their elements held together by a covalent bond that contain partially positive and negative charges, which results in a difference in the charges' electronegativity difference (usually ranging between 0.4 and 0.7).
- PCl5 is <u>non-polar</u> with a symmetric geometry
- CoS is <u>polar</u>
- XeO3 is <u>polar</u>, with a trigonal pyramidal molecular geometric
- SeBr2 is <u>polar</u> as the difference their electronegativity is about ).5
<span>Balanced chemial equation:
2NaI(aq)+Hg2(NO3)2(aq) →Hg2 I2 (s) + 2 NaNO3 (aq)
You can see it better if I use latex:
As per the phases this is the interpretation:
The symbols (aq) stands for aquous meaning that the compound is dissolved in water.
The symbol (s) stands for solid, meaning tha the compound precipitate and is not dissolved in water.</span><span>
</span>
2NaI(aq)+Hg2(NO3)2(aq) →Hg2 I2 (s) + 2 NaNO3 (aq)
You can see it better if I use latex:
As per the phases this is the interpretation:
The symbols (aq) stands for aquous meaning that the compound is dissolved in water.
The symbol (s) stands for solid, meaning tha the compound precipitate and is not dissolved in water.</span><span>
</span>
Answer:
(a) Cr²⁺: 1s² 2s²2p⁶ 3s²3p⁶ 3d⁴; (b) eight
Explanation:
(a) Electron configuration of Cr
(i). Locate chromium in the Periodic Table.
It's Element 24, so in Period 4, Group 3.
(ii). Write its electron configuration
Remember that Cr is one of those exceptions to the Aufbau principle.
Instead of the predicted electron configuration of [Ar] 4s²3d⁴, we get the configuration [Ar] 4s3d⁵.
The reason is that this this configuration minimizes electron repulsion.
(b) Write the electron configuration for Cr²⁺.
Now, we must remove two electrons from a chromium atom.
The electron in the 4s orbital is removed first, because this orbital is further from the nucleus, making electrons easier to remove.
So, we remove the 4s electron, and then a 3d electron.
The electron configuration of Cr²⁺ is
[Ar]3d⁴ or 1s² 2s²2p⁶ 3s²3p⁶ 3d⁴
(c). Electrons with n + l = 3
The orbitals with n + l = 3 are those covered by the third arrow down in the order of orbital energies:
2p (n = 2, l = 1) and 3s (n = 3, l = 0)
The 2p orbitals can hold six electrons, and the 3s orbital can hold two.
Both subshells are filled in a Cr²⁺ ion, so there are eight electrons
with n+ l = 3.
