Answer:
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Explanation:
Answer is...
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Answer:
<em>the mass of the original unstable particle is</em><em> 1115.08 MeV/c²</em>
Explanation:
The momentum of a particle is determined by:
p = e B R
where
- B is the magnetic field
- R is the radius of curvature
- e is the energy of the particle
Therefore,
p = e B R kg · m/s
We can transform the units to MeV/c and we do that by taking:
e = 0.511 MeV and
c = 3 × 10⁸ m/s
Therefore,
p = 300 B R MeV/c
p = 300(0.250 T)(1.33 m) MeV/c
p = 99.75 MeV/c
The energy of the unstable decayed particle is determined as:
E = √ [m²c⁴ + p²c²]
where
- m is the mass of the particle
- c is the speed of light
- p is the particle's momentum
Therefore,
E = E_p + E_(π⁻)
E = √[ (938.3)² + (99.75)² ] + √[ (139.5)² + (99.75)² ]
E = 1115.08 MeV
Since the particle was initially at rest, its energy is only rest-mass energy so its <em>mass will be 1115.08 MeV/c²</em>
