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ipn [44]
4 years ago
8

A point charge Q is located a short distance from a point charge 3Q, and no

Physics
1 answer:
ruslelena [56]4 years ago
5 0

The other force is also 'F'.

The forces on any two charged particles are opposite and EQUAL, and proportional to the product of the charges.

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find the net force on the moon due to the gravitational attraction of the earth and sun assuming right angles
lesya [120]

Use F = (GMm)/r^2.

7 0
3 years ago
A torpedo is launched underwater, targeting a naval vessel about 5,000 m away. How can the vessel detect the torpedo before it r
DanielleElmas [232]

The options are missing and they are;

Select one:

A. By seeing it flying above the water

B. By listening for it in the air

C. By listening for it underwater

D. None of the above: it won’t be able to detect it in time.

Answer:

OPTION C is the correct answer:By listening for it underwater

Explanation:

Due to the fact that the ships and other boats have underwater microphones because on most cargo ships the engine is to loud so they use microphones underwater to detect torpedos. Thus, the vessel can detect the torpedo by listening under water

8 0
3 years ago
Mechanical waves propagate or move through a medium because
Schach [20]
Because the move through water
7 0
3 years ago
A dog starts at the origin and runs forward at 6m/s for 1.5s and then turns around to fetch the ball by running backward at 7m/s
Vera_Pavlovna [14]

Answer:

Total time elapsed between the start and when he returns with the ball is 7.5s

Explanation:

From the question,

- The dog starts at the origin and runs forward at 6m/s for 1.5s. First, we will determine the distance covered while running forward.

From

Speed = Distance / Time

Distance = Speed × Time

Speed = 6m/s

Time = 1.5s

∴ Distance = 6m/s × 1.5s

Distance = 9m

That is, the dog covered a distance of 9m while running forward.

- The dog turns around and runs backward at 7m/s for 3s. Now, we will also determine the distance the dog covered backwards.

Distance = Speed × Time

Speed = 7m/s

Time = 3s

Distance = 7m/s × 3s

Distance = 21m

The dog's displacement from the origin is 21m - 9m = 12m

Now, to calculate how much time has elapsed between the start if the dog runs back to the origin at 4m/s, we will first determine the time the dog spent back to the origin and then add to the time spent for the first two distances.

To get back to the origin, the dog needs to cover 12m

From

Speed = Distance / Time

Time = Distance / Speed

Distance = 12m

Speed = 4m/s

∴ Time = (12m) / (4m/s)

Time = 3s

Therefore, the dog spent 3s to run back to the origin.

Hence, total time elapsed = 1.5s + 3s + 3s

Total time elapsed = 7.5s

8 0
3 years ago
PLEASE help with this question!
Ainat [17]

Answer:

the answer might the number 2

Explanation:

6 0
3 years ago
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