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Masteriza [31]
3 years ago
8

A car starts at the top of a hill with 200 J of energy, and rolls down a frictionless surface. The isolated system consists of t

he car, hill, and earth. What happens to the energy of the system as the car moves down the hill?
The total energy stays the same but is converted from being stored as kinetic energy into elastic potential energy as it moves.

The total energy stays the same but is converted from being stored as gravitational potential energy into kinetic energy of the car as it moves.

The total energy decreases and is converted from being stored as gravitational potential energy into kinetic energy as it moves.

The total energy decreases and is converted from being stored as elastic potential energy into kinetic energy as it moves.
Physics
1 answer:
Kamila [148]3 years ago
6 0

Answer:

The total energy stays the same but is converted from being stored as gravitational potential energy into kinetic energy of the car as it moves.

Explanation:

the law of conservation of energy states that the total energy of an isolated system remains constant, and since it is gaining speed that energy will be kinetic

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The momentum of light, as it is for particles, is exactly reversed when a photon is reflected straight back from a mirror, assum
LenKa [72]

Answer:

a)   E = 2.00 10³ J , b)   I = 6.66 10⁻⁶ N s , c)   F = 1.66 10⁻⁶ N

Explanation:

a) The intensity is defined as the power per unit area

          I = P / A

          P = I A

Power is energy for time

         P = E / t

We replace

        E / t = I A

        E = I A t

        E = 1.0 10³ 2.0 1.00

        E = 2.00 10³ J

b) The moment is

       p = U / c

In the case of a reflection the speed is reversed, so the moment

      Δp = 2 U / c

       I = Δp

       I = 2 U / c

       I = 2.00 10³/3 10⁸

       I = 6.66 10⁻⁶ N s

c) The defined impulse is

        I = F t

       F = I / t

For a time of 1 s

       F = 6.66 10⁻⁶ / 1

       F = 1.66 10⁻⁶ N

d) Suppose n small mass mirror m = 10 10⁻³ kg, we write Newton's second law

        F = ma

        a = F / m

        a = 1.66 10⁻⁶ / 10 10⁻³

         a = 1.66 10⁻⁴ m / s

We see that the acceleration is very small and attended to increase the mass of the mirror will be less and less, so the assumption of no twisting of the mirror is very reasonable

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