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Masteriza [31]
3 years ago
8

A car starts at the top of a hill with 200 J of energy, and rolls down a frictionless surface. The isolated system consists of t

he car, hill, and earth. What happens to the energy of the system as the car moves down the hill?
The total energy stays the same but is converted from being stored as kinetic energy into elastic potential energy as it moves.

The total energy stays the same but is converted from being stored as gravitational potential energy into kinetic energy of the car as it moves.

The total energy decreases and is converted from being stored as gravitational potential energy into kinetic energy as it moves.

The total energy decreases and is converted from being stored as elastic potential energy into kinetic energy as it moves.
Physics
1 answer:
Kamila [148]3 years ago
6 0

Answer:

The total energy stays the same but is converted from being stored as gravitational potential energy into kinetic energy of the car as it moves.

Explanation:

the law of conservation of energy states that the total energy of an isolated system remains constant, and since it is gaining speed that energy will be kinetic

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Two balls with masses of 2.0 kg and 6.0 kg travel toward each other at speeds of 12 m/s and 4.0 m/s, respectively. If the balls
Alina [70]

Answer:

The kinetic energy lost in the collision is 48 J

Explanation:

Given;

mass of the first ball, m₁ = 2.0 kg

mass of the second ball, m₂ = 6.0 kg

initial speed of the first ball, u₁ = 12 m/s

initial speed of the second ball, u₂ = 4 m/s

let v be the final velocity of the two balls after the inelastic collision

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

2 x 12 + 6 x 4 = v(2 + 6)

48 =  8v

48 / 8 = v

v = 6 m/s

The initial kinetic energy of the balls is calculated as;

K.E₁ = ¹/₂m₁u₁² + ¹/₂m₂u₂²

K.E₁ = ¹/₂(2)(12²) + ¹/₂(6)(4)²

K.E₁ = 144 + 48

K.E₁ = 192 J

The final kinetic of the balls is calculated as;

K.E₂ = ¹/₂(m₁ + m₂)(v²)

K.E₂ = ¹/₂(2 + 6)(6²)

K.E₂ = ¹/₂(8)(6²)

K.E₂ = 144 J

The lost in kinetic energy of the balls is K.E₂ - K.E₁ = 144 J - 192 J = -48 J

Therefore, the kinetic energy lost in the collision is 48 J

5 0
3 years ago
Pls answer quick I need to get the answer rn
lora16 [44]
I think it is False because as the Gad relajases fuel it doesn’t move as much anymore
3 0
2 years ago
Frictional force is caused by the interaction of a body with​
zheka24 [161]

Answer:

Frictional force always acts parallel to two planes in contact with each other and in a direction opposite to that of relative motion of the two bodies. 2. Frictional forces are caused due to intermolecular interactions between the bodies.  Frictional force is more for rough surface and less for smooth surfaces.

6 0
3 years ago
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An empty truck traveling at 10 km/h has kinetic energy. How much kinetic energy does it have when loaded so that its mass and it
Katena32 [7]

Answer:

8 time increase in K.E.

Explanation:

Consider Mass of truck = m kg and speed = v m/s then

K.E. = 1/2 ×mv²

If mass and speed both are doubled i.e let m₀ = 2m and v₀ = 2v then

(K.E.)₀ =  1/2 ×2m(2v)²

(K.E.)₀ = 8 (1/2 × mv²) = 8 × K.E.

7 0
3 years ago
An object is placed in a fluid and then released. Assume that the object either floats to the surface (settling so that the obje
Irina18 [472]

Answer:

A. Always true

Explanation:

This is because, the buoyancy force is always present whenever and object is placed in a fluid. The magnitude of this  buoyancy force is always equal to the weight of the fluid    displaced by the object according to Archimedes' principle. This principle is true irrespective of whether the object floats or not. When any object is inserted in a fluid, the buoyancy force is always present irrespective of whether it floats or not.  

7 0
3 years ago
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