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ss7ja [257]
3 years ago
5

You go rock climbing with a pack that weighs 70 N and you reach a height of 30 m. how much work did you do to lift your pack? If

you finished the climb in 10 minutes (600 s), what was your power?
Physics
1 answer:
Vikentia [17]3 years ago
8 0
When you climb, earth exerts gravitational force on pack in downward direction(pointing towards the center of earth).
In order to climb, you need to work against work done by gravity on the pack.
Hence work done by you = work done by gravity on pack 
                                        = Force x displacement = 70 x 30 = 2100 J.
 
So you need to do 2100 joules of work to lift your pack.

Power is the rate of work done.
Therefore power = work done by you/time(in seconds)
                            =     2100/600 =3.5 watts 
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3 years ago
A 69-kg student sitting on a hardwood floor does not slide until pulled by a 260-N horizontal force. find coefficient of frictio
salantis [7]

Answer:

μ = 0.385

Explanation:

Given that,

The mass of the student, m = 69 Kg

The horizontal force applied, F = 260 N

The normal force acting on the body, weight = mg = 69g  N

                                                                                    = 676.2 N

The coefficient of friction acting on a body is equal to the force acting on the body to the normal force acting on the body due to gravitation.

The formula for coefficient of friction,

                                    μ =  F / N

Substituting the values in the above equation,

                                     μ = 260 N / 676.2 N

                                        = 0.385

Hence, the  coefficient of friction, μ = 0.385

6 0
3 years ago
A gas bottle contains 0.650 mol of gas at 730 mm Hg pressure. If the final pressure is 1.15 atm, how many moles of gas were adde
AlekseyPX

Answer:

0.779 mol

Explanation:

Since the gas is in a bottle, the volume of the gas is constant. Assuming the temperature remains constant as well, then the gas pressure is proportional to the number of moles:

p \propto n

so we can write

\frac{p_1}{n_1}=\frac{p_2}{n_2}

where

p1 = 730 mm Hg = 0.96 atm is the initial pressure

n1 = 0.650 mol is the initial number of moles

p2 = 1.15 atm is the final pressure

n2 is the final number of moles

Solving for n2,

n_2 = n_1 \frac{p_2}{p_1}=(0.650 mol)\frac{1.15 atm}{0.96 atm}=0.779 mol

6 0
3 years ago
Read 2 more answers
Energy is transferred as the heat between two objects, one with a temperature of 5 C and the other with a temperature of 20 C. I
Delicious77 [7]

Answer:

Final temperature is located between 5 °C and 20 °C.

Explanation:

The object with high temperature transfers energy to the object with low temperature until thermal equilibrium is reached, that is, when both objects have the same temperature.

Q_{H} = -Q_{L}

C_{H}\cdot (20^{\textdegree}C - T) = -C_{L}\cdot (5^{\textdegree}C-T)

20\cdot C_{H} - C_{H}\cdot T = -5\cdot C_{L}+ C_{L}\cdot T

(C_{H}+C_{L})\cdot T=20\cdot C_{H} + 5\cdot C_{L}

T = 20\cdot\frac{C_{H}}{C_{L}+C_{H}} + 5\cdot \frac{C_{L}}{C_{L}+C_{H}}

Now, let consider three scenarios:

Scenario 1 - C_{H} = C_{L]

T = 12.5^{\textdegree}C

Scenario 2 - C_{H}>> C_{L}

T = 20^{\textdegree}C

Scenario 3 - C_{H}

T = 5^{\textdegree}C

Final temperature is located between 5 °C and 20 °C.

8 0
3 years ago
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Answer:

40°

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And the angle made by reflected ray with the normal to the surface is called angle of reflection.

by the law of reflection angle of incidence is equal to the angle of reflection

hence the answer to the question is 40°        ( because ∠i =∠r )

7 0
3 years ago
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