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torisob [31]
3 years ago
14

A basketball seems flat after being left out in cold. Once it warms up, it seems fine. Explain why.

Physics
1 answer:
Tema [17]3 years ago
4 0

The cold air increases pressure on the basketball, causing it to appear flat. When it warms up that pressure is taken off, so the basketball is at it's normal state.

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A crate of oranges is shoved across a grocery store floor with a force of 100 N for a distance of 1 meter. The crate travels an
navik [9.2K]

The statements that are true are;

  • the magnitude of work done by frictional forces on the crate is 100 J
  • the magnitude of work done by the applied force on the crate is 100 J
<h3>What is work done?</h3>

Work is said to be done when te force applied travels a distance in the direction of the force. Now we can see that when the force is applied by shoving the crate, work is done, an additional work is done by friction to bring the crate to a stop.

Hence, the following are true;

  • the magnitude of work done by frictional forces on the crate is 100 J
  • the magnitude of work done by the applied force on the crate is 100 J

Learn more about work: brainly.com/question/18094932?

4 0
2 years ago
What is walking,jogging, and map reading skills considered as
Karo-lina-s [1.5K]
I looked it up and it gave me educational exercise, but I don't know if it is right.
4 0
3 years ago
Read 2 more answers
Calculate the acceleration if you push with a 20-N horizontal force on a 2-kg block on a horizontal friction-free air table
Afina-wow [57]
Acceleration = force / mass = 20 / 2 = 10 m/s^2
3 0
3 years ago
An electric current of 200 A is passed through a stainless steel wire having a radius R of 0.001268 m. The wire is L = 0.91 m lo
denis23 [38]

Answer:

The value is   T_m  =  435.2 \  K

Explanation:

From the question we are told that  

   The  current is  I  =  200 \ A

   The radius is  R =  0.001268 \  m

   The  length of the wire is  L  =  0.91 \  m\

    The  resistance is  R  =  0.126 \  \Omega

    The  outer surface temperature is  T _o  =  422.1 \  K

    The average thermal conductivity is  \sigma  =  22.5 W/mK

   

Generally the heat generated in the stainless steel wire is mathematically represented as  

    Q =  \frac{Power}{ \pi r^2L}

     Q =  \frac{I^2 R}{ \pi r^2L}

=>   Q =  \frac{200^2 * 0.126}{3.142 *  (0.001268)^2 * 0.91}

=>   Q =  1.096*10^{9}\  W/m^3

Generally the middle temperature is mathematically represented as

      T_m  =  T_o  + \frac{Q * r^2 }{ 6  * \sigma }

       T_m  =  422.1  +  \frac{1.096*10^{-9} * 0.001268^2}{6 * 22.5}

       T_m  =  435.2 \  K

4 0
3 years ago
A hockey puck sliding at 60.0m/s slows uniformly to 20.0m/s while travelling 800.0m.
julia-pushkina [17]
A) -3.75 meters/second
A=(20^2-80^2)/(2x800)
=(400-6400)/1600
=-6000/1600
=-3.75
B) 16 seconds
t=(20-80)/-3.75
=-60/-3.75
=16
3 0
3 years ago
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