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3 years ago

Which quantity is proportional to 45/3

Mathematics

1 answer:

Eduardwww [97]3 years ago

7 0

Answer:

15/1, 90/6

Step-by-step explanation:

45/3 = 15

Anything not equal to 15 is not a solution

90/10 = 9

90/6 = 15

15/1 = 15

135/6 = 22.5

30/1 = 30

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A book is 0.33 meters long. How many millimeters long is it?

Phoenix [80]

we know that

$1\ meter=1,000\ millimeters$

by proportion

Find how many millimeters are in $0.33$ meters

$\frac{1,000}{1} \frac{mm}{m} =\frac{x}{0.33} \frac{mm}{m} \\ \\x=1,000*0.33 \\ \\ x=330\ mm$

therefore

the answer is

$330\ mm$

7 0

3 years ago

1+secA/sec A = sin^2 A / 1-cos A

Fofino [41]

Answer: see proof below

Step-by-step explanation:

$\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}$

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

Proof LHS → RHS

$\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}$

$\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}$

$\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}$

$\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}$

$\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}$

$\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark$

3 0

3 years ago

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NeX [460]

20÷10= 2
50÷10= 5
ratio is2:5

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