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3 years ago

13

I NEED THEM ASAP 20 Points

1 answer:

Mrrafil [7]3 years ago

8 0

Answer: (i think these are right)

experimental: 27.08% theoretical: 50% ?

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What is the value of the expression -38-16-(-23)?<br> O-31<br> O-45<br> O-54<br> O-77

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-31

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$-38-16-(-23) \\ \\ =-38-16+23 \\ \\ =-54+23 \\ \\ =-31$

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1 year ago

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2 years ago

Question 3 A study was performed to determine whether men and women differ in their repeatability in assembling components on pr

Fed [463]

Answer:

There is no sufficient evidence to support the claim that men and women differ in repeatability for this assembly task

Step-by-step explanation:

Given

Let subscript 1 represent men and 2 represent women, respectively.

$n_1 = 25$

$n_2 = 21$

$s_1 = 0.98$

$s_2 = 1.02$

$\alpha = 0.02$

Required

Determine if here is enough evidence

First, we need to state the hypotheses

$H_o: \sigma_1^2 = \sigma_2^2$

$H_1: \sigma_1^2 \ne \sigma_2^2$

Next, calculate the test statistic using:

$F = \frac{s_1^2}{s_2^2}$

$F = \frac{0.98^2}{1.02^2}$

$F = 0.923$

Calculate the rejection region;

But first, calculate the degrees of freedom

$df_1 =n_1 - 1$

$df_1 =25 - 1$

$df_1 =24$

$df_2 = n_2 -1$

$df_2 = 21 - 1$

$df_2 = 20$

Using the F Distribution: table

$c = \frac{\alpha}{2}$

$c = \frac{0.02}{2}$

$c = 0.01$

At 0.01 level (check row 20 and column 24), the critical value is:

<em></em> $f_{0.01,24,20} = 2.86$ <em> --- the upper bound</em>

At 0.01 level (check row 24 and column 20), the critical value is:

$f_{0.01,20,24} = 2.74$

Calculate the inverse F distribution.

$f_{0.99,20,24} = \frac{1}{f_{0.01,20,24}} = \frac{1}{2.74} =0.365$ ---- the lower bound

The rejection region is then represented as:

$0.365 < Test\ Statistic < 2.86$

If the test statistic falls within this region, then the null hypothesis is rejected

$F = 0.923$ --- Test Statistic

$0.365 < 0.923 < 2.86$

<em>The above inequality is true; so, the null hypothesis is rejected.</em>

<em>This implies that, there is no sufficient evidence.</em>

7 0

3 years ago