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3 years ago

Which characteristics do Jupiter and Saturn share? Check all that apply

Chemistry

2 answers:

andrey2020 [161]3 years ago

8 0

Answer:

Explanation:

I took the assignment :D

Natasha2012 [34]3 years ago

6 0

Answer:

The correct answers are first, fourth, fifth

Explanation:

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A science club made pine wood cars. Each car was set on the same track and then released. The distance traveled was measured. Li

Minchanka [31]

Isn't this a math problem?
If it is the the answer should be 102.

10 decimeters=1 meter

27x10=270
270-168=102

7 0

3 years ago

Is methane used as fule<br> gas true or false<br>

Hitman42 [59]

Answer:

its true methane is used as a fuel gas

Explanation:

4 0

2 years ago

Write the electron configuration for N and N-3. How many electrons are in the valence energy level?

Alinara [238K]

Non-valence electrons: 1s22s22p6. Therefore, we write the electron configuration for Na: 1s22s22p63s1. What is the highest principal quantum number that you see in sodium's electron configuration? It's n = 3, so all electrons with n = 3 are valence electrons, and all electrons with n < 3 are non-valence electrons.

8 0

3 years ago

This is very urgent please hurry!!?!!??!

yawa3891 [41]

Answer:

The greatest acceleration when the unbalanced force is applied will be experienced in :

A) The box with a mass of 2 kg

Explanation:

According to second law of motion the external unbalanced force is directly proportional to rate of change of momentum.

F = (Final momentum - initial momentum)/time

Force is equal to the product of mass and acceleration

F = m x a

Here a= acceleration

m = mass of the object

If Force is constant then acceleration is inversely proportional to mass

$a =\frac{F}{m}$

A) The box with a mass of 2kg

F = 8 N

$a =\frac{8}{2}$

a = 4 m/s2

B) The box with the mass of 4kg

$a =\frac{8}{4}$

a = 2 m/s2

C) The box with a mass of 6kg

$a =\frac{8}{6}$

a = 1.33 m/s2

D) The box with a mass of 8kg

$a =\frac{8}{8}$

a = 1 m/s2

3 0

3 years ago

Salt in crude oil must be removed before the oil undergoes processing in a refinery. The

irina1246 [14]

Answer:

$\large \boxed{0.64 \, \%}$

Explanation:

Assume you are using 1 L of water.

Then you are washing 4 L of salty oil.

1. Calculate the mass of the salty oil

Assume the oil has a density of 0.86 g/mL.

$\text{Mass of oil} = \text{4000 mL} \times \dfrac{\text{0.86 g}}{\text{1 mL}} = \text{3440 g}$

2. Calculate the mass of salt in the salty oil

$\text{Mass of salt} = \text{3440 g} \times \dfrac{\text{5 g salt}}{\text{100 g oil}} = \text{172 g salt}$

3. Calculate the mass of salt in the spent water

$\text{Mass of salt} = \text{1000 g water} \times \dfrac{\text{15 g salt}}{\text{100 g water}} = \text{150 g salt}$

4. Mass of salt remaining in washed oil

Mass = 172 g - 150 g = 22 g

5. Concentration of salt in washed oil

$\text{Concentration} = \dfrac{\text{22 g}}{\text{3440 g}} \times 100 \, \% = \mathbf{0.64 \, \%}\\\\\text{The concentration of salt in the washed oil is $\large \boxed{\mathbf{0.64 \, \%}}$}$

3 0

3 years ago