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garik1379 [7]
3 years ago
10

Which characteristics do Jupiter and Saturn share? Check all that apply

Chemistry
2 answers:
andrey2020 [161]3 years ago
8 0

Answer:

1

4

5

Explanation:

I took the assignment :D

Natasha2012 [34]3 years ago
6 0

Answer:

The correct answers are first, fourth, fifth

Explanation:

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An astronaut weighs 104 newtons on the moon,where the strength of gravity is 1.6 newtons per kilogram
belka [17]
I'd say he ways about 35 kilograms, but I'm probably wrong, xD

6 0
4 years ago
Read 2 more answers
In an attempt to study the variation of the boiling point of mixture (B + C), the teacher immerses a thermometer probe into the
grandymaker [24]

Answer:

All answers attached in the pictures above.

3 0
2 years ago
When potassium chromate, k2cro4, dissolves in water, what ions are produced?
Alexandra [31]
When potassium chromate dissolves in water, the ions that are produced are potassium and chromate.

This can be expressed as follows:
Potassium chromate in water will give the following ions:
<span>2K+ + CrO4^2- </span>
7 0
3 years ago
How many moles of nacl are required to make 250 ml of a 3.00 m solution?
choli [55]
The molarity is calculated using the following rule:
molarity = number of moles of solvent / volume of solution (in liters)

We have the volume of solution = 250 ml = 0.25 liters and the molarity = 3 m

Substituting in the equation, we get:
3 = number of moles / 0.25
number of moles = 3 x 0.25 = 0.75 moles
4 0
3 years ago
A student heats a sample of hydrate once, and the mass of the sample and the evaporating dish is 16.428 g. After a second heatin
jolli1 [7]

Answer:

12.371 g

Explanation:

Given :

m_{evaporating\ dish}=1.135\ g

m_{evaporating\ dish}+m_{Hydrate\ sample}=25.637\ g

m_{evaporating\ dish}+m_{First\ heated\ sample}=16.428\ g

m_{evaporating\ dish}+m_{Second\ heated\ sample}=13.266\ g

Mass of salt hydrate:

m_{evaporating\ dish}=1.135\ g

m_{evaporating\ dish}+m_{Hydrate\ sample}=25.637\ g

m_{Hydrate\ sample}=25.637-m_{evaporating\ dish}\ g=25.637-1.135\ g=24.502\ g

Mass of salt anhydrous:

m_{evaporating\ dish}=1.135\ g

m_{evaporating\ dish}+m_{Second\ heated\ sample}=13.266\ g

m_{Second\ heated\ sample}=m_{salt\ anhydrous}=13.266-m_{evaporating\ dish}\ g=13.266-1.135\ g=12.131\ g

Mass of water:

m_{water}=m_{Hydrate\ sample}-m_{salt\ anhydrous}=24.502-12.131\ g=12.371\ g

m_{water}=12.371\ g

4 0
4 years ago
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