175.8 g NaCl to moles:
(175.8 g)/(58.44 g/mol) = 3.008 mol NaCl
Molarity = moles of solute/volume of solution in liters
(3.008 mol NaCl)/(1.5 L) = 2.0 M.
The molarity of this solution would be 2.0 M.
Answer:
P₂= 116.7 atm
Explanation:
Here apply the Boyle's law equations that states :at constant temperature the volume of a dry mass of a gas is inversely proportional to its pressure.
This is simplified as;
P₁V₁=P₂V₂ where P is pressure and V is volume
Given that;
P₁=1
V₁=1.81 m³
P₂=?
V₂=1.55*10^-2 m³
Apply the formula
1*1.81 =P₂*1.55*10^-2 m³
1.81/1.55*10^-2 =P₂
P₂= 116.7 atm
Answer:
41.17
Explanation:
n Zn = mass / m.wt
= 8.75 /(65.4) = 0.1338 mole
n HCL = ( from the balanced equation )
<u> 2HCL</u> <u>Zn</u>
2mole → 1 mole
x mole → 0.1338mole
n HCL = .268 mole
M= mole/liter
6.50= 0.268/x
so u have0.04117 liter = 41.17 ml
M(Li2O) = 2M(Li) +M(O)= 2*6.9 +16.0 = 29.8 g/moi
Answer A. 29.9 g/mol